Answer:
a.0.8664
b. 0.23753
c. 0.15866
Step-by-step explanation:
The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between
a. N164.50 and N185.50?
b. greater than N180.00?
c. less than N168.00?
We solve the above question using z score formula
z = (x-μ)/σ/√n where
x is the raw score,
μ is the population mean = N175
σ is the population standard deviation = N42
n is random number of sample = 36
a. Between N164.50 and N185.50?
For x = N 164.50
z = 164.50 - 175/42 /√36
z = -1.5
Probability value from Z-Table:
P(x = 164.50) = 0.066807
For x = N185.50
z = 185.50 - 175/42 /√36
z =1.5
Probability value from Z-Table:
P(x=185.50) = 0.93319
Hence:
P(x = 185.50) - P(x =164.50)
= 0.93319 - 0.066807
= 0.866383
Approximately = 0.8664
b. greater than N180.00?
x > N 180
Hence:
z = 180 - 175/42 /√36
z = 5/42/6
z = 5/7
= 0.71429
Probability value from Z-Table:
P(x<180) = 0.76247
P(x>180) = 1 - P(x<180) = 0.23753
c. less than N168.00?
x < N168.
z = 168 - 175/42 /√36
z = -7/42/6
z = -7/7
z = -1
Probability value from Z-Table:
P(x<168) = 0.15866
The inequality:
48 < 6 n
6 n > 48
n > 48 : 6
n > 8
Answer: n = { 9, 10, 11 } ( 3 values )
We can prove this: 48 < 6*9 or 48 < 54, 48 < 60, 48 < 66
Answer:
Try splitting the figure up and use the basic area formulas to help u
Step-by-step explanation:
Answer:
Step-by-step explanation:
you can start by factoring x
x(2x³-x²-18x+9)
you can group terms in parentheses strategicly
x(2x³-18x-x²+9)=x[2x(x²-9)-(x²-9)]
now we can factor x²-9
x(x²-9)(2x-1)
factor the diference of two squares x²-9=x²-3²
x(x-3)(x+3)(2x-1)
so the roots are found by using the zero product rule
x(x-3)(x+3)(2x-1)=0 will give
x=0, x-3=0 so x=3, x+3=0 so x=-3, 2x-1=0 so x=1/2
from left to right
-3, 0, 1/2, 3
Answer
Step-by-step explanation:
