Question

Mr. and Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 85%. If they have four children, what is the probability that exactly one of their four children will have that trait? Round your answer to the nearest thousandth.

Answer 1

Answer:

the probability that exactly one of their four children will have that trait is 0.287%

Step-by-step explanation:

Given;

The probability that a child born to them have a particular trait is

P = 85% = 0.85

The probability that a child born to them will not have a particular trait is

P' = 1 - P = 1-0.85 = 0.15

The probability that exactly one of four children have the trait is:

P(1) = P × P' × P' × P'

P(1) = 0.85 × 0.15 × 0.15 × 0.15

P(1) = 0.00286875

P(1) = 0.287 %

the probability that exactly one of their four children will have that trait is 0.287%