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3 years ago

Select the equivalent expression . ( 8^ -5 2^ -2 )^ -4 =?

Mathematics

1 answer:

Vikki [24]3 years ago

6 0

Answer: C

Step-by-step explanation:

When there is division inside a set of parentheses, you can distribute the power to each term. When you take a power to another power, you multiply the powers.

-5 x -4 = 20

-2 x -4 = 8

So your answer is:

$\frac{8^2^0}{2^8}$

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Solve (2x + 3) - (9x - 3)

Diano4ka-milaya [45]

Answer:

-7x + 6

Step-by-step explanation:

3 0

3 years ago

Given α and β are Supplementary. Show the necessary steps.

user100 [1]

Answer:

$\alpha = 108\degree, \: \beta = 72\degree$

Step-by-step explanation:

α and β are Supplementary (given)

$\therefore \alpha + \beta = 180\degree.... (1)$

It is given that:

$\alpha= \frac{3}{2} \beta$

Plugging the value of α in equation (1), we find:

$\frac{3}{2} \beta + \beta = 180\degree$

$\therefore \frac{3+2}{2} \beta = 180\degree$

$\therefore \frac{5}{2} \beta = 180\degree$

$\therefore \beta = 180\degree\times \frac{2}{5}$

$\therefore \beta = 72\degree$

$\implies \alpha= \frac{3}{2} \times 72\degree= 108\degree$

So,

$\alpha = 108\degree, \: \beta = 72\degree$

7 0

3 years ago

The perimeter of a rectangle is 46in and the diagonal is 17 in

dmitriy555 [2]

Answer + explaination

p=2*(L+l)=46

L+l=46:2

L+l=23

(L+l)^2=529

(L^2+l^2)+2l*L=529

D= V L^2+l^2= 17

L^2+l^2=289

so 289+2l*L=529

2l*L=529-289=240

l*L=240:2

A=120

4 0

3 years ago

The weight W of an aluminum flatboat varies directly with the length L of the boat. If a 6-foot boat weighs 102 pounds, then w

AnnZ [28]

Answer:

The 11 foot boat ways 187 pounds

Step-by-step explanation:

102 / 6 = 17

17 * 11 = 187

3 0

3 years ago

The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a

LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

$dP/dt=P(aP-b)$

$dP=P(aP-b)dt$

$1/(dP^2-bP)dP=dt$

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

$1/(d-b/P)\cdot{P^2} dP$

let

$u=d-b/P$

$du/dP=b/P^2$

$dP=$ $\int\limits {P^2/b} \, du$

$P=lnu/b$

Substitute u in:

$P=ln(d-b/P)/b$

Therefore the equation is:

$ln(d-b/P)/b=t$

We simplify:

$d-b/P=e^b^t$

$P=b/(d-e^b^t)$

As t increases to infinity P will decrease

6 0

3 years ago