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Mama L [17]
3 years ago
9

Write the expression below using exponents. 2 x 2 x 2 x 4 x 4

Mathematics
2 answers:
eimsori [14]3 years ago
6 0

Answer:

(2^3)(4^2)

Step-by-step explanation:

myrzilka [38]3 years ago
3 0

[ Answer ]

\boxed{2^{3}  \ * \ 4^{2} }

[ Explanation ]

Exponent: A number that tells you how many times to multiply a number by itself

2 * 2 * 2 * 4 * 4

You need to multiply 2 by itself 3 times. Therefore, 2 * 2 * 2 turns into: 2^{3}

You multiply 4 by itself 2 times. Therefore, 4 * 4 turns into: 4^{2}

Now, multiply them by each other: 2^{3} \ * \ 4^{2}

Remember, you do not multiply the top number by the bottom number. The top number ONLY tells how many times the bottom numbers needs to be multiplied by itself.

\boxed{[ \ Eclipsed \ ]}

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Two physics students are doing a side competition during a game of bowling, seeing who can toss a ball with the larger momentum.
dem82 [27]

Answer:

she should beat a speed of  v₂ = 6.04 m/s in order to win the competition

Step-by-step explanation:

Since the momentum p is defined as

p = m*v

where

m= mass of the ball

v= velocity of the ball

denoting 1 and 2 as the first and second bowler , then to reach the momentum of the first bowler

p₂=p₁

therefore

m₁*v₁ = m₂*v₂

v₂ = v₁ * (m₁/m₂)

replacing values

v₂ = v₁ * (m₁/m₂) =8.6 m/s * (4.5 kg/6.4 kg ball) = 6.04 m/s

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6 0
3 years ago
Given P space equals space P subscript 0 space plus space rho g h, your objective is to determine the uncertainty of P by measur
son4ous [18]

Answer:

the g's contributing term for the overall uncertainty of P is  dP_g =  [\frac{dg}{g}]

Step-by-step explanation:

From the question we are told that

   The pressure is   P  = P_o + \rho gh

The first step in determining the uncertainty of P in by obtaining the terms in the equation contributing to it uncertainty and to do that we take the Ln of both sides of the equation

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Then the next step is to differentiate both sides of the equation

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=>    \frac{dP}{P}  =  \frac{dP_o}{P_o} + \frac{d \rho}{\rho} +\frac{d g}{g} + \frac{d h}{h}

We asked to obtain the contribution of the term g to the uncertainty of P

This can deduced from the above equation as

     dP_g =  [\frac{dg}{g}] P

8 0
3 years ago
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The answer is 64
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