You add 25 and 22 and it adds up to 47 so the answer is 47
Answer:
The highest common factor for both 102 and 153 is
GCF- 51
Step-by-step explanation:
51*3= 153
51*2=102
Just count the number of squares:
(9+5)*2=14*2=28
Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value ![C(0)= $16,000](https://tex.z-dn.net/?f=C%280%29%3D%20%2416%2C000)
Depreciation rate is ![r=\frac{4.5}{100}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B4.5%7D%7B100%7D)
<h3>∴ r=0.045</h3>
Period , t=5 years
![C(t)=C(0)(1-r)^t](https://tex.z-dn.net/?f=C%28t%29%3DC%280%29%281-r%29%5Et)
Substitute the values we get
![C(5)=16000(1-0.045)^5](https://tex.z-dn.net/?f=C%285%29%3D16000%281-0.045%29%5E5)
![=16000(0.955)^5](https://tex.z-dn.net/?f=%3D16000%280.955%29%5E5)
![=16000(0.7943)](https://tex.z-dn.net/?f=%3D16000%280.7943%29)
∴ ![C(5)=12708.8](https://tex.z-dn.net/?f=C%285%29%3D12708.8)
<h3>The value C(t) of the car after 5 years is $
12709</h3>
The answer is 800.
To find this, multiply 10 times 8 to find the number you are dividing. (80) now, multiply 80 by 10. (800)
1/10 of 800 is 80, which is ten times as much as 8.