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yuradex [85]
2 years ago
8

What is the value of M?

Mathematics
1 answer:
stepan [7]2 years ago
4 0

Answer:

25 Or A

Step-by-step explanation:

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Help me plz and explain how u got it
mario62 [17]
The baskets that DO have eggs in the baskets are  2 3 4 26 34 46 
i am not 100% sure if its right but i think it is 
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5 0
3 years ago
Read 2 more answers
Arrange in order from greatest to least using the > sign : 8.067 / 8.006/8.06​
Assoli18 [71]

Answer:

8.067>8.06>8.006

Step-by-step explanation:

Remember that what ever the number is after the decimal is the the greatest.

5 0
3 years ago
What is the length of the hypotenuse of the right triangle? Enter your answer in the box.
ki77a [65]

Answer:

10 ft

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

let h be hypotenuse, then

h² = 6² + 8² = 36 + 64 = 100 ( take the square root of both sides )

h = \sqrt{100} = 10

The hypotenuse is 10 ft

5 0
3 years ago
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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
Plzzz help!!!!!!!!!!!!!!!!
REY [17]

Answer:

B) The function has a maximum value of (1)

Step-by-step explanation:

The given function has a maximum value, as its curve is inverted. The maximum value is the largest (y) value that a function can attain. As one can see, this value is (1), because the (y-coordinate) of the highest point on its curve is (1). This function has no minimum value, its endpoints go on infinitely in a negative direction.

3 0
3 years ago
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