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3 years ago

Select ALL the correct answers.

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer: I think it’s A the cylinder

Step-by-step explanation:

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A boy has only dimes and quarters in his piggy bank. if he has 70 coins worth 12 dollars and 40 cents altogether, how many quart

dlinn [17]

Let us bear in mind the equivalent value of these coins:

One dime = $0.10

One quarter = $0.25

Let x = number of dimes

y<span> = number of quarters</span>

Since the boy has 70 coins in total, we can say that:

<span>x + y = </span><span>70 </span>(can be written as x = 70 – y)

Since the boy has a total of $12.40, we can say that:

0.10x + 0.25y = 12.40

To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)

0.10(70 – y) + 0.25y = 12.40

7 – 0.10y + 0.25y = 12.40

0.15y = 5.40

y = 36

X = 70 – 36

X = 34

Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span>

34 dimes = $3.40

36 dimes = $9.00

<span>Total </span><span>$12.40</span>

7 0

2 years ago

Read 2 more answers

Find the value of the missing angles in the following figures

Veseljchak [2.6K]

Answer:

ans: ii) 87° and iii) 60°

Step-by-step explanation:

ii)

y° = 180° - ( 56° + 37°)

missing angle on triangle is alternate angle of y° so are equal and sum of angles of triangle is 180°

iii)

x° + 2x° = 180°

sum of co interior angles is 180°

7 0

3 years ago

Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each

emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

$A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2$

Jake wants to increase the area by 50%, so the new area would be:

$A'=168(1.5) \\ \\ A'=252ft^2$

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

$(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives$

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

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