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3 years ago

ASAP NEED TO KNOW IF IM CORRECT 5/6 x 575=2,875/6

Mathematics

2 answers:

EleoNora [17]3 years ago

7 0

Answer:

Yes, that is correct.

The answer 149.166666667 or 479 1/6

The exact answer is 149.166666667

In fraction form the answer is 2,875/6

Hunter-Best [27]3 years ago

5 0

Answer:

Yes you are indeed correct $(\frac{5}{6} )(575) = \frac{2875}{6}$

Step-by-step explanation:

$(\frac{5}{6} )(575) = \frac{2875}{6}$

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Solar panels use the suns energy to generate power.A town wants to install 28 solar panels in an array.What are all the possible

Anna11 [10]

Answer:

The possible arrays are: (1,28) , (2,14) , (4,7)) , (7,4) , (14,2) and (28,1)

Step-by-step explanation:

Here, the total number of solar panels to be installed = 28

Let us assume the installed array has m rows and n columns.

Now, the total panels installed = Number of rows x Number of columns

or, 28 = m n

The following cases are possible for array:

(a) When m = 1, n = 28 (as m x n = 28)

So, here array has 1 row with 28 columns.

(b) When m = 2, n = 14 (as m x n = 28)

So, here array has 2 row with 14 columns.

So, here array has 4 row with 7 columns.

(d) When m = 7, n = 4 (as m x n = 28)

So, here array has 7 row with 4 columns.

(e) When m = 14, n = 2 (as m x n = 28)

So, here array has 14 row with 2 columns.

(f) When m = 28, n = 1 (as m x n = 28)

So, here array has 28 row with 1 columns.

4 0

4 years ago

Dena's softball team can win (W) or lose (L) each game. Which of the following are elements in the sample space for 2 softball g

Leviafan [203]

In a softball game, the odds are only win or lose the game. When 2 games are already being considered, the elements in the sample space are already 2 in each set. The sets are {W,W}, {W,L}, {L,W} and {L,L}. Hence, there are 4 sets all in all to describe the odds of the two games.

8 0

4 years ago

What is 248,470 rounded to the nearest thousand

Sati [7]

Rounded to the nearest thousand, 248,470 would be 248,000. Remember that the thousands digit is the fourth from the right.

8 0

3 years ago

I need help PLEASE!!!!

nikitadnepr [17]

Answer:

OPTION A

OPTION B

OPTION D

Step-by-step explanation:

Given that a bag of apples cost 'a' dollars.

A bag of oranges cost 'a + 2' dollars.

Therefore, one bag each of apples and oranges should cost: a + a + 2 dollars.

Since, Dorie buys 5 bags of apples and Oranges, it would have costed her:

5(a + a + 2)

= 5(2a + 2)

= 10a + 10

Hence, OPTION A, B and D are the correct answers.

6 0

3 years ago

An old-fashioned bicycle has two differently sized wheels. The circumference of the front wheel is 9 feet larger than the circum

Lady_Fox [76]

So, the bicycle looks like the one in the picture below.

now, the circumference of the smaller wheel, will just be C = 2πr, with a radius of "r".

we also know that the large wheel has a circumference that is 9 feet larger than the small one, so, since the small one has a circumference of 2πr, then the large one will have a circumference of 2πr + 9.

after Thomas cycled for a while, the large did 500 revolutions, or times around, whilst the small one did 1400, since it's smaller. On that time, they covered however, the same amount of ground, since they're on the same bike.

The amount covered by the small one in 1400 cycles, is 1400(2πr), that's how much ground it covered.

The amount covered by the large one in 500 cycles, is 500(2πr + 9).

And we know that ground covered, is the same for both, therefore, we also know that 1400(2πr) = 500(2πr + 9).

$\bf \stackrel{small~wheel}{1400(2\pi r)}~~=~~\stackrel{large~wheel}{500(2\pi r+9)}\implies 14(2\pi r)=5(2\pi r+9)
\\\\\\
28\pi r=10\pi r+45\implies 18\pi r=45\implies r=\cfrac{45}{18\pi }
\\\\\\
\boxed{r=\cfrac{5}{2\pi }}$

so, how much ground did they cover anyway?

well, we could use either, since we know what the radius is, hmmmm let's use say the small wheel's circumference,

$\bf 1400(2\pi r)\implies 1400\left(\underline{2\pi }\cdot \cfrac{5}{\underline{2\pi }} \right)\implies 1400(5)\implies \stackrel{feet}{7000}$

8 0

4 years ago

Read 2 more answers