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malfutka [58]
3 years ago
14

Which ratios form a proportion? Select all that apply.

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0

Answeri think e?

Step-by-step explanation:

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Find two numbers if their difference is 16 and their ratio is 5:7.
myrzilka [38]

Let us say that the numbers are x and y. The given clues are:

1. x – y = 16         (so x is the larger number)

2. y / x = 5 / 7

 

rewriting eqtn 2 in terms of y:

y = (5/7) x

 

combining 1 and 2:

x – (5/7) x = 16

(2/7) x = 16

x = 56

 

y = (5/7) x = 40

 

So the two numbers are 56 and 40.

3 0
3 years ago
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Evaluate –3ab when a = –2 and b = –5.
UNO [17]
Simple.....

you have:

-3ab--->> a=-2  b=-5

Or-->>

-3(-2)(-5)

Simplify....

-3(10)

-30

Thus, your answer.
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4 years ago
What is the place if 6 in 34.76
Paladinen [302]
The answer is Hundredths place
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4 years ago
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Which expression represents the sum of (2x-5y and (x+y) ?
gayaneshka [121]
I have no clue you have to do something like x2-x1 over y1-y2 and you get yoyu answer from that. 
8 0
3 years ago
Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

3 0
4 years ago
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