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kodGreya [7K]
2 years ago
5

The measures of angle Q R S and angle S R T have a sum of 90 ∘ .

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

Answer:

c

Step-by-step explanation:

bc blah blah blahhhhhhhhhhhhhhhhh and yessir

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Can help me with this?
Tanzania [10]

Answer:I’m sorry this is hard I don’t think I have the right answer chose C

Step-by-step explanation:

3 0
3 years ago
PUT THESE NUMBERS IN ORDER GREATEST TO LEAST ✔✔ I WILL ADD BRAINLIST
Fiesta28 [93]

Answer:

2 12/16, 2 18/25, and lastly 2.

Step-by-step explanation:

Since 2 is least, we can put that at the end. That leaves us with 2 18/25 and 2 12/16. Since 12/16 is greater, we will put that as the greatest. 2 18/25 is in the middle. Hope this helps!

6 0
3 years ago
The first term in the sequence below is 2.
Art [367]
-7n + 9 because the common difference is -7, so you have -7n, and then by plugging in the term numbers and the values, you find out that you need to add 9 to the -7n, so the answer is -7n + 9

3 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
Three of these expressions are equal to the volume of the barn shown. Which expression is not?
timurjin [86]

The statement that does not match the others is the one at lower right.

_____

The barn's volume can be decomposed into a rectangular prism and a triangular one. Thus the <em>upper right</em> expression is a true represenation of the barn's volume:

... Volume of triangular prism + Volume of rectangular prism

The volume of a <em>rectangular prism</em> is the product of its dimensions. The dimensions of the rectangular prism portion of the barn's volume are a, b, c, so the volume of that portion is ...

... Volume of rectangular prism = a·b·c

The volume of a <em>triangular prism</em> is the area of the triangular base multiplied by the length of the prism. Here, the triangular base has base dimension b and height (d-c), so its area is ...

... Area of triangular barn end = (1/2)b(d-c)

Since the length of the barn is "a", the volume of the triangular prism is ...

... Volume of triangular prism = (1/2)b(d-c)a = (1/2)·a·b·(d-c)

The <em>total volume</em> is the sum of the volumes of the parts ...

... a·b·c + (1/2)·a·b·(d-c) . . . . . . matches the <em>upper right</em> selection

This can be factored by removing a·b to outside parentheses:

... a·b·((1/2)·(d-c) + c) . . . . . . . . . matches the <em>lower left</em> selection

___

Since the two left selections match the one at upper right, the odd one is the one at lower left.

7 0
3 years ago
Read 2 more answers
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