1 ) 3 t ( t + 2 ) - 3 t² =
= 3 t² + 6 t - 3 t² = 6 t = 6 · 19 = 114
2 ) - ( 3 a - 2 b ) - 3 ( - a- b ) =
= - 3 a + 2 b + 3 a + 3 b = 5 b
Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
Given:
mean, u = 0
standard deviation σ = 1
Let's determine the following:
(a) Probability of an outcome that is more than -1.26.
Here, we are to find: P(x > -1.26).
Apply the formula:
Thus, we have:
Using the standard normal table, we have:
NORMSDIST(-1.26) = 0.1038
Therefore, the probability of an outcome that is more than -1.26 is 0.1038
(b) Probability of an outcome that
Answer:
4
Step-by-step explanation:
If you mean root of x, 24-8=16
square root of 16=4
