Using S = ut + 1/2gt², from rest, u = 0
S = 1/2gt², g ≈ 9.8 m/s²
S = <span>1/2 *9.8*3²
</span>S = 0.5<span> *9.8*3*3
</span>
<span>S ≈ 44.1 m</span>
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
Answer:
slope is (y1-y2)/x1-x2 pick two points on the line
Step-by-step explanation:
19+x/2=4
multiply 2 on both sides
19+x=4 times 2
19+x=8
subtract 19 on each side
x=8-19
subtract
x=-11
Answer:
f(x) = (-1/2)(x^2 + 8x - 15)
Step-by-step explanation:
This function has two roots: -3 and 5. Most likely it is a quadratic (all of which have two roots).
Then f(x) = a(x + 3)(x - 5)
The graph goes through (1. 8): Therefore, y = 8 when x = 1:
f(1) = a(1 + 3)(1 - 5) = 8, or
a(4)(-4) = 8, or
-16a = 8, which leads to a = -1/2.
Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or
f(x) = (-1/2)(x^2 + 8x - 15)
