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Lena [83]
3 years ago
6

A die is thrown 300 times with frequencies for the outcome 1 2 3 4 5 6, whats the probablity of getting a prime number, given th

e frequencies are 42 60 55 53 60 and 30 respectively?
Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

58.3% to the nearest tenth.

Step-by-step explanation:

The prime numbers from 1 to 6 are 2,3 and 5.

The probability of a prime number taken from the result of the 300 throws:

=  (sum of the frequencies for 2, 3 and 5)  /  ( total throws)

= (60 + 55 + 60) / 300

=  0.5833 or 58.3%.

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Step-by-step explanation:

You multiply 5 times 5 and you get 25 or you could count 5 fingers 5 times

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3 years ago
2(a³+b²+11)+1(3+a³+b+11)
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Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

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2a^3+2b^2+22+a^3+b+14

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Therefore, the simplified form is 3a^3+2b^2+b+36

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4 years ago
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Novay_Z [31]

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3 years ago
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Answer:

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Step-by-step explanation:

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10 ÷ 2 : 6 ÷2

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Svetach [21]

Answer: the answer is -16x+7y+4z

Step-by-step explanation:

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3 years ago
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