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nekit [7.7K]
3 years ago
7

WIll GIVE BRAINLISET PLS ANSWER ASAP!!!!!!!!

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer:

4 units

Step-by-step explanation:

For explanation see the attachment.

Natalija [7]3 years ago
7 0

Answer:

4 units

Step-by-step explanation:

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A rectangle is 4 times as long as it is wide. The perimeter of a rectangle is 50 cm. What are the dimensions of the rectangle?
marissa [1.9K]
We use the equation 2x+8x=50.

10x=50
x=5

The rectangle will be 20 cm long and 5 cm wide.

Hope this helps!
7 0
3 years ago
Read 2 more answers
What is the ratio of the radius of a circle to its circumference 12π 1πr 1π 2π
aleksklad [387]
The circumference is (2 pi) (radius) . The ratio of radius to circumference is (1)/(2 pi).
4 0
3 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
2. Wpisz taką liczbę, aby rozwiązaniem równania była liczba 2.
lys-0071 [83]
I didn’t understand but when I understand I will help you
5 0
3 years ago
-1/2x+6 <br> who ever answers this gets 10 points
gogolik [260]
The answer would be -1/2(X+3)
6 0
3 years ago
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