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3 years ago

Solve each equation by taking square roots NEED FHIS ANSWER ASAP ILL GIVE BRAINLIEST

Mathematics

1 answer:

stepan [7]3 years ago

8 0

Answer:

your answer are above

Step-by-step explanation:

hope it helps you

have a great day!!

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Please prove this........

Crazy boy [7]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

Proof LHS → RHS

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago

Item 13 Factor out the coefficient of the variable. The expression 14y+38 factored is

klemol [59]

Answer:

2(7y+19)

Step-by-step explanation:

14y+38=2(7y+19)

8 0

3 years ago

Will mark brainlist plz anwser

never [62]

The width of the court is 30 feet!

5 0

3 years ago

Read 2 more answers

What is 10*9*8*7*6*5*4*3*2*1?

nordsb [41]

Welcome to the factorial world :) Remember the Exclamation Point ( ! ) on the calculator, that is called factorial.
For instance: 1! = 1
2! = 1 x 2
3! = 1 x 2 x 3
and so on
10! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 = 3628800
Crazy enough, 0! is actually equal to 1, try that on your calculator XD

6 0

3 years ago

What type of number is 12i+360

QveST [7]

Answer:

Complex number.

Step-by-step explanation:

3 0

2 years ago