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vagabundo [1.1K]
3 years ago
15

Solve each equation by taking square roots NEED FHIS ANSWER ASAP ILL GIVE BRAINLIEST

Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

your answer are above

Step-by-step explanation:

hope it helps you

have a great day!!

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a previous analysis of paper boxes showed that the standard deviation of the length is 9mm. What is the 98% confidence interval
il63 [147K]
We cannot calculate the confidence interval without the sample size.  However, for the second question, the sample size needed would be 49.

The formula we use is

n=(\frac{z_{\frac{\alpha}{2}}\times \sigma}{E})^2

To find the z-score:
Convert 98% to a decimal:  0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is closest to a z-score of 2.33.

Using the z-score, our standard deviation (9) and our margin of error (3), we have:
n=(\frac{2.33(9)}{3})^2=(6.99)^2=48.86\approx 49
6 0
3 years ago
Tyler has 2 liters of water and drink half of it. How many mililiters of water does he have left?
Serga [27]

Answer:

1000 mililiters

Step-by-step explanation:

There are 1000 mililiters in one liter. Since there are two liters, it means there´s 2000 mililiters. He drink half of it, so 1000 mililiters are left.

7 0
4 years ago
Simplify the first trigonometric expression by writing the simplified form in terms of the second expression (1/1-cosx)-(cos/1+c
garik1379 [7]

(\frac{1}{1-cos(x)})-(\frac{cos(x)}{1+cos(x)})

cscx is  1/sinx

maybe they want us to use pythagorean identity

cos^2(x)+sin^2(x)=1

I notice we have 1-cos(x) and 1+cos(x), if we multiply them, we get 1-cos^2(x)

and if we look at the pythagorean identity and minus cos^2(x) from both sides, we get

sin^2(x)=1-cos^2(x)

since csc(x)=\frac{1}{sin(x)}, csc^2(x)=\frac{1}{sin^2(x)}=\frac{1}{1-cos^2(x)}

(recall that (a-b)(a+b)=a²-b²)

match the denomenators of the original fraction

multiply first fraction by \frac{1+cos(x)}{1+cos(x)} and the 2nd by \frac{1-cos(x)}{1-cos(x)}


(\frac{1+cos(x)}{1-cos^2(x)})-(\frac{cos(x)(1-cos(x))}{1-cos^2(x)})=

((csc^2(x))(1+cos(x)))-((csc^2(x))(cos(x)-cos^2(x)))=

csc^2(x)+csc^2(x)cos(x)-(csc^2(x)cos(x)-csc^2(x)cos^2(x)=

csc^2(x)+csc^2(x)cos(x)-csc^2(x)cos(x)+csc^2(x)cos^2(x)=

csc^2(x)+csc^2(x)cos^2(x)=

csc^2(x)(1+cos^2(x)), hmm, to get ride of those cos(x)

look to the pythagorean identity again


sin^2(x)+cos^2(x)=1, force one side into form 1+cos^2(x)

1+cos^2(x)=2-sin^2(x), recall that since csc(x)=1/sin(x), sin(x)=1/csc(x) and sin^2(x)=1/(csc^2(x))

1+cos^2(x)=2-\frac{1}{csc^2(x)}

subsituting


csc^2(x)(1+cos^2(x))=

(csc^2(x))(2-\frac{1}{csc^2(x)})= distributing

2csc^2(x)-\frac{csc^2(x)}{csc^2(x)}=

2csc^2(x)-1 is the simplified expression

8 0
3 years ago
Evaluate 16x^0 if x= -3
balu736 [363]

Answer:

16

Step-by-step explanation:

16x^0= \\\\16(-3)^0= \\\\16(1)= \\\\16

Hope this helps!

5 0
3 years ago
Read 2 more answers
We want to use a half liter of water. How many milliliters would that be?
natta225 [31]
500 milliliters because 1 liter=1000 milliliters
7 0
3 years ago
Read 2 more answers
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