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3 years ago

Bro 100 points if u halp c========3

Mathematics

2 answers:

julia-pushkina [17]3 years ago

8 0

Me after hearing someone cough on my $8 round trip flight to Italy.

Rina8888 [55]3 years ago

6 0

Answer:

wham there you go cursed meme

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Debbie is N years old. Edna is 3 years older than Debbie and Shawn is twice as old as Debbie. The expression n+n+3+2n gives the

34kurt

N + n + 3 + 2n = (sum of age)

First change the problem and add 1 in front of the variables (n)

1n + 1n + 3 + 2n = (sum of age)

Next add the like terms which are 1n, 1n, and 2n

1n + 1n = 2n
2n + 2n = 4n

Now 3 is left by itself add it to the problem

4n + 3

SIMPLIFIED EXPRESSION IS 4n + 3

8 0

4 years ago

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

<u>Factored form of a parabola</u>

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

6 0

2 years ago

Help me please idk this

Burka [1]

The answer is 3 3/8 miles

6 0

3 years ago

Read 2 more answers

Help please!!!!!!!!!

Liono4ka [1.6K]

-6 And 8 ok it make me have 20 c

4 0

3 years ago

Read 2 more answers

Please answer this (photo below)

lozanna [386]

Answer:

Please see attached image for the graph

Step-by-step explanation:

To graph the elevation versus time, we start by plotting the first point at time zero (when the climb begins) when Zane is 20 meters below the edge (-20 meters). This corresponds to the point (0, -20).

One second later (1 in the horizontal axis), Zane has moved up 4 meters, now reaching -16 meters. This is the point (1, -16) on the graph.

One second later at time 2 seconds, he is another 4 meters up which corresponds to the point (2, -12) on the graph.

you can go on like this plotting more points on the graph.

Please see the attached image that illustrates this and shows the appropriate line that represents Zane's position versus time (pictured in red)

7 0

4 years ago