We are given the equation of a line
y = -2x + 1
We have to find the value of y at three different values of x i.e. x = 0, -3 and 1
In order to find the value of y at any given x, simply replace x by that number.
So, for x=0, we will replace x by 0 to find the value of y. So y will be:
y = -2(0) + 1
y = 1
This can be expressed as an ordered pair as (0,1)
Similarly for x=-3, we get
y = -2(-3) + 1 = 6 + 1
y = 7
This can be expressed as an ordered pair as (-3, 7)
And, finally for x=1, we get:
y= -2(1) + 1 = -2 + 1
y = -1
This can be expressed as an ordered pair as (-1, -1)
Answer: 23 is 69160. You subtract high school from associates and multiplty youe answer by 10.
Step-by-step explanation:
From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8.
Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.
<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>
Answer:
Step-by-step explanation:
=> ![\sqrt[7]{m^3}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bm%5E3%7D)
![\sqrt[7]{}= ^\frac{1}{7}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7B%7D%3D%20%5E%5Cfrac%7B1%7D%7B7%7D)
=> 
=>
33 because 6x5=30 then plus 3 equals 33
