The last one is the right answer b/c 7 plus 0.30 for each topping, -> t
I'm reading this as

with

.
The value of the integral will be independent of the path if we can find a function

that satisfies the gradient equation above.
You have

Integrate

with respect to

. You get


Differentiate with respect to

. You get
![\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20y%7D%3D%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20y%7D%5Bx%5E2e%5E%7B-y%7D%2Bg%28y%29%5D)


Integrate both sides with respect to

to arrive at



So you have

The gradient is continuous for all

, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is
Answer:
Step-by-step explanation:
Emery is paid 15 dollars an hour and she worked 38 hours
15*38=570 dollars just from the hourly wage
the commission is 2.25% and her sales were 3,200 dollars
(3200*2.25)/100=72
total=570+72=642
Answer:
6.68181818182
Step-by-step explanation:
Answer:
John lost $6841.42.
Step-by-step explanation:
Let's find out how much John paid for the stock he bought. Each share cost $58.02. He bought 120 shares. Multiply the price by the number of shares.
58.02 x 120 = 6962.40
He sold the stock for $120.98 -- a huge loss! (We are not told that the $120.98 is the selling price of one share, so I'm assuming that's what John sold all his shares for.)
Find the difference to see what his loss was.
$6962.40 - $120.98 = $6841.42 LOST!