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Oksana_A [137]
3 years ago
12

In a typical week you drive 34.85 km on Monday, 28.23 km on

Mathematics
1 answer:
Tasya [4]3 years ago
6 0

Answer:

63.08 km

Step-by-step explanation:

To find how far you drive, add up the km from only Monday and Tuesday, since you aren't driving on Friday

34.85 + 28.23

= 63.08

So, you would drive 63.08 km

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What are some ways to decribe the relationships between sets of numbers
lina2011 [118]
By their increase or decrease
4 0
3 years ago
The Rawlins family has travelled 600 km on their vacation. This has taken them 8 hours. If they continued at the same rate, how
spin [16.1K]

Answer:

B. 28 hours

Step-by-step explanation:

GIVEN :- <em>Time taken by family to travel 600 km is 8 hours</em>

CALCULATIONS :-

<em>To calculate the time to travel 2100 km, we need to calculate distance traveled in 1 hour</em>

<em>Distance traveled in 1 hour = 600 km ÷ 8</em>

<em>                                              = 75 km</em>

<em>Time required to travel 2100 km = 2100 ÷ 75</em>

<em>                                                         = </em><em>28 hours</em>

Therefore time required to travel 2100 km is 28 hours.


6 0
3 years ago
What is the area of a rhombus with dimensions of 22 inches and 10 inches?
docker41 [41]
The answer to the problem is 220
3 0
3 years ago
Read 2 more answers
A chemist wishes to mix a solution that is 6% acid. She has on hand 14 liters of a 4% acid solution and wishes to add some 10% a
jonny [76]

she should add 7 liters of 10% acid solution

Explanation

Step 1

set the equation:

a) let X represents the amount os solution that is 4% acid

let Y represents the amount os solution that is 10% acid

so

I)

\begin{gathered} \frac{4}{100}X+\frac{10}{100}Y=\frac{6}{100}(x+y) \\  \end{gathered}

if he has 14 liters of 4% acid solution

x=14

\begin{gathered} \frac{4}{100}X+\frac{10}{100}Y=\frac{6}{100}(X+Y) \\ \frac{4}{100}*14+\frac{10}{100}Y=\frac{6}{100}(X+Y) \\ 0.56+0.1Y=0.06(14+Y) \\ 0.56+0.1Y=0.84+0.06Y \\  \end{gathered}

Step 2

solve the equation :

\begin{gathered} 0.56+0.1Y=0.84+0.06Y \\ subtract\text{ 0.06Y in both sides} \\ 0.56+0.1Y-0.06Y=0.84+0.06Y-0.06Y \\ 0.56+0.04Y=0.84 \\ subtract\text{ 0.56 in both sides} \\ 0.56+0.04Y-0.56=0.84-0.56 \\ 0.04Y=0.28 \\ divide\text{ both sides by 0.04} \\ \frac{0.04Y}{0.04}=\frac{0.28}{0.04} \\ Y=7 \end{gathered}

therefore,

she should add 7 liters of 10% acid solution

I hope this helps you

8 0
1 year ago
Does anybody know the measure of JLM?
WARRIOR [948]

Measure of ∠JLM = m∠60°

6 0
2 years ago
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