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Leno4ka [110]
2 years ago
11

Yan ate 1/4 of a pizza. What friction of the pizza is left?

Mathematics
1 answer:
wariber [46]2 years ago
3 0

Answer:

3/4

Step-by-step explanation:

If he/she ate 1/4 then there would still be 3/4

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Assume there are 365 days in a year.
Dahasolnce [82]
The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.

To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.
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Rewrite 3√5^2 with a rational exponent.
Law Incorporation [45]

Answer:

C. 5 2/3

Step-by-step explanation:

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3 years ago
A sugar cookie recipe calls for 5 cups of flour for every 1 cups of sugar. If y y is the number of cups of flour and x x is the
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Yy=5(xx)

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Cathy earns $32 after babysitting for 5 hours. How much money does she earn per hour?
telo118 [61]
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Read 2 more answers
All about simulitious equations​
Korolek [52]

Answer:

On occasions you will come across two or more unknown quantities, and two or more equations

relating them. These are called simultaneous equations and when asked to solve them you

must find values of the unknowns which satisfy all the given equations at the same time.

Step-by-step explanation:

1. The solution of a pair of simultaneous equations

The solution of the pair of simultaneous equations

3x + 2y = 36, and 5x + 4y = 64

is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides

to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.

2. Solving a pair of simultaneous equations

There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a

single equation which involves the other unknown. The method is best illustrated by example.

Example

Solve the simultaneous equations 3x + 2y = 36 (1)

5x + 4y = 64 (2) .

Solution

Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation

6x + 4y = 72 (3)

Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:

6x + 4y = 72 − (3)

5x + 4y = 64 (2)

x + 0y = 8

5 0
2 years ago
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