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Dimas [21]
3 years ago
10

Write

n^{2} x)" alt="cot^{2} x (1+tan^{2} x)" align="absmiddle" class="latex-formula"> Then simplify the expression so no quotients appear
Mathematics
1 answer:
ASHA 777 [7]3 years ago
7 0

Step-by-step explanation:

From Trig

1 + tan²x = Sec²x

Also

Sec²x = 1/cos²x

Now

Cot²x = 1/tan²x = cos²x/sin²x

Putting all together

Cot²x(1+tan²x)

= Cot²x(sec²x)

= cos²x/sin²x(1/cos²x)

cos²x on the numerator and that one the denominator cancels out

we have

= 1/sin²x

From Trig

1/sin²x = cosec²x

So Our Answer = cosec²x.

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Abena wanted to buy a bag and had saved for eight consecutive weeks. She saved $2.00 im the first week,$4.00 in the second week,
Paladinen [302]

Answer: 88 dollars

Step-by-step explanation: We will follow the pattern of 2s, so 2 4 6 8 10 12 14 16 is how much she saved over the course of all 8 weeks. 2 plus 4 equals 6. 6 plus 8 equals 14. 10 plus 12 is 22. 14 plus 16 is 30. 6 plus 14 is 30 and 22 plus 36 is 58. Last of all, 58 plus 30 is 88

3 0
3 years ago
What is the solution to the following equation? 5(2x − 14) + 23 = 7x − 14
g100num [7]
X=11

 Hope this helps your welcome
7 0
3 years ago
Read 2 more answers
The expression equivalent to (3y+8x)+(4x-8y)
Fiesta28 [93]

Answer:

= 12x - 5y

Step-by-step explanation:

Given that:

=(3y+8x)+(4x-8y)

Now simplify by removing brackets:

= 3y + 8x + 4x - 8y

Add the same terms:

= 12x - 5y

i hope it will help you!

3 0
3 years ago
Consider the system of equations
lyudmila [28]
4)
I:3x+4y=67
II:5x-y=35

to eliminate y when they are added one of the equations must contain -ay and the other +ay (with a being some number)
in this case we have in I already a positive term and in II a negative, but they have different numbers
by using multiplication (property of equations) we can multiply II by 4 so the negative and positive parts match

II*4: 20x-4y=140

when I and 4*II get added this results in
3x+20x+4y-4y=67+140
23x=207

5)
in this case I and II were added which can be seen in the left side of the equation((3x+4y)+(5x-y)=8x+3y), so to get the right side we have to also add the right sides 67+35=102

so the full equation would be:
8x+3y=102
4 0
4 years ago
Determine the equation of the line passing through the points (3,1) and (5,−1).
katrin [286]

Answer:

y=-x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-1)/(5-3)

m=-2/2

m=-1

y-y1=m(x-x1)

y-1=-1(x-3)

y-1=-x+3

y=-x+3+1

y=-x+4

5 0
3 years ago
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