All categories

2 years ago

Find the values of y=m(x)=-√-x for x = –8.41, –7.84, –7.29, –6.76, –6.25, 0

Mathematics

1 answer:

ICE Princess25 [194]2 years ago

5 0

Just be patient: y = -sqrt(8.41) = calculator (negative value) and so on. The last one is 0! :)

You might be interested in

Use partial quotient 28 divided by 514

Ann [662]

The result is 18 r 10

5 0

2 years ago

141.1933-67.53 =<br> (Divided, not minus)

Sphinxa [80]

Answer: I think its 2.09

Step-by-step explanation:

But i'm not sure.

5 0

2 years ago

Use the pythagoren theorem to solve x

defon

Well the equation is (A^2)+(B^2)=(C^2)

A= x
B= 2x
C will always be the longest side because it is the Hypotenuse = 25

So if you plug in those numbers into the equation...

(x^2) + (2x^2) = (25^2)

x^2 + 4x^2 = 625

Combine like terms

5x^2 = 625

Divide by five to both sides

x^2 = 125

Then Square root,

x = sqrt(125)

x = sqrt(25* 5)

x = 5sqrt(5)

3 0

3 years ago

What is the sum of the first 70 consecutive odd numbers? Explain.

expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

$\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1$

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

$\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)$

The second sum is simply the sum of N ones:

$\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N$

So, the final result is

$\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2$

which ends the proof.

5 0

2 years ago

An n × n matrix B has characteristic polynomial p(λ) = −λ(λ − 3) 3 (λ − 2) 2 (λ + 1). Which of the following statements is false

asambeis [7]

Answer:

Only d) is false.

Step-by-step explanation:

Let $p=p(\lambda)=\lambda(\lambda-3)^3 (\lambda-2)^2 (\lambda+1)$ be the characteristic polynomial of B.

a) We use the rank-nullity theorem. First, note that 0 is an eigenvalue of algebraic multiplicity 1. The null space of B is equal to the eigenspace generated by 0. The dimension of this space is the geometric multiplicity of 0, which can't exceed the algebraic multiplicity. Then Nul(B)≤1. It can't happen that Nul(B)=0, because eigenspaces have positive dimension, therfore Nul(B)=1 and by the rank-nullity theorem, rank(B)=7-nul(B)=6 (B has size 7, see part e)

b) Remember that $p(\lambda)=\det(B-\lambda I)$ . 0 is a root of p, so we have that $p(0)=\det(B-0 I)=\det B=0$ .

c) The matrix T must be a nxn matrix so that the product BTB is well defined. Therefore det(T) is defined and by part c) we have that det(BTB)=det(B)det(T)det(B)=0.

d) det(B)=0 by part c) so B is not invertible.

e) The degree of the characteristic polynomial p is equal to the size of the matrix B. Summing the multiplicities of each root, p has degree 7, therefore the size of B is n=7.

8 0

2 years ago