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Tems11 [23]
2 years ago
5

WILL GIVE BRAINLIEST!!

Mathematics
2 answers:
kvv77 [185]2 years ago
8 0

Answer:

hi

Step-by-step explanation:

i think so,it is 19

have a nice day

Zanzabum2 years ago
6 0

Answer:

19 is the correct answer

hope it is helpful to you

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how could i answer this question? "suppose 2 friends want to share 5 cookies evenly. Interpret the remainder in two different wa
laiz [17]
They both can have two cookies and then split the fith one in half
8 0
3 years ago
Solve the equation below by factoring
MA_775_DIABLO [31]

Answer:

The first one is n=4,-1

Second one in exact form

m =   \frac{7 +  \sqrt{73} }{4}

Second one in decimal form

m = 3.88600093... \:  - 0.38600093...

4 0
2 years ago
Help please ASAP!!!! I NEED CORRECT ANSWERS ONLY FOR BRAINLIEST
scoray [572]

f(x) =5-3x

g(x)=x²-1

f(g(x)) = f(x²-1)

replacing x by x²-1 in the function f(x) , we get

f(x²-1) = 5-3(x²-1) = 5-3x²+3 =8-3x²

f(g(x)) =8-3x²

now finding g(f(x))

g(5-3x)

replacing x by 5-3x in the function g(x)

g(5-3x) = (5-3x)²-1

g(5-3x) = 5²-30x +9x²-1 = 9x²-30x +24

g(f(x))= 9x²-30x +24

f(g(x)) =8-3x²

in option third the f(g(x)) is -3x³+8 which is incorrect

8 0
2 years ago
PLS CAN SOMEONE HELP ME PLS
EastWind [94]

Answer:

20 m

Step-by-step explanation:

Let the length of the perpendicular dropped from vertex C to segment AB be x

By geometric mean property:

x =  \sqrt{16 \times 9}  \\  \\ x =  \sqrt{144}  \\  \\ x = 12 \: m \\  \\ By \: Pythagoras \: Theorem: \\  \\ Distance \: across \: the \: pond \\  \\  =  \sqrt{ {16}^{2} +  {12}^{2}  }  \\  \\  =  \sqrt{256 + 144}  \\  \\  =  \sqrt{400}  \\  \\  = 20 \: m

7 0
3 years ago
F(h) = 45+<br> 20<br> h +0.5<br> g(h) = 45 + 33(0.5) (h+0.5)
larisa [96]

Steps:

Question 1:

Step 1: Multiply both sides by h+0.5.

Step 2: Factor out variable f.

Step 3: Divide both sides by h^2+0.5h.

Question 2

Let's solve for g.

Step 1: Divide both sides by h.

Answers:

1: f=45h+42.5/h²+0.5h

2: g=16.5h+53.25/h

Please mark Brainliest

<em><u>Hope this helps.</u></em>

8 0
3 years ago
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