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alexdok [17]
3 years ago
14

Which equation represents the function graphed on the coordinate plane? g(x) = |x + 4| – 2 g(x) = |x – 4| – 2 g(x) = |x – 2| – 4

g(x) = |x – 2| + 4. Which equation represents the function graphed on the coordinate plane?
g(x) = |x + 4| – 2
g(x) = |x – 4| – 2
g(x) = |x – 2| – 4
g(x) = |x – 2| + 4

On a coordinate plane, an absolute value graph has a vertex at (negative 4, negative 2).
Mathematics
2 answers:
saul85 [17]3 years ago
7 0

Answer:A

Step-by-step explanation:

Misha Larkins [42]3 years ago
6 0

Answer:

g(x)=|x+4|-2

Step-by-step explanation:

All the absolute value functions given in the option are of the form:

g(x)=|x-h|+k, where (h,k) is the vertex

From your description the absolute value graph has vertex at (-4,-2)

Hence h=-4 and k=-2.

We substitute to get:

g(x)=|x--4|+-2

We simplify to get:

g(x)=|x+4|-2

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Evaluate for x=2<br> |2x-18| + |3x-7|
KatRina [158]

Answer:

15

Step-by-step explanation:

2(2) - 18 = -14 |-14| = 14

3(2) -7 = -1 |-1| = 1

14+1=15

5 0
3 years ago
What is the sum of the geometric series
lbvjy [14]
If S denotes the sum of the first n terms of a geometric series with first term a and common ratio r, then

S=a+ar+ar^2+\cdots+ar^{n-3}+ar^{n-2}+ar^{n-1}
rS=ar+ar^2+ar^3+\cdots+ar^{n-2}+ar^{n-1}+ar^n
\implies S-rS=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n
\implies (1-r)S=a(1-r^n)
\implies S=a=\dfrac{1-r^n}{1-r}

Using summation notation, you have

S=\displaystyle\sum_{x=1}^nar^{x-1}=\sum_{x=0}^{n-1}ar^x=a\dfrac{1-r^n}{1-r}

In this case, you have a=2, r=\dfrac12, and n=16. So the value of the sum is

\displaystyle\sum_{x=0}^{15}2\left(\frac14\right)^x=2\dfrac{1-\left(\frac14\right)^{16}}{1-\frac14}\approx2.67

Rounded to the nearest whole number, the answer would be 3.
4 0
3 years ago
Read 2 more answers
7(3x -4) = 49 <br><br><br><br> can you help me
kotykmax [81]

Answer:

3 2/3

Step-by-step explanation:

7(3x-4)=49

21x-28=49

21x=77

x=3 2/3

3 0
3 years ago
To be considered similar, two polygons must have corresponding sides that are in proportion.
Agata [3.3K]
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4 0
3 years ago
Ella grew 3 over 4 of an inch last year. Ben grew 2 over 3 of an inch last year. How much more did Ella grow than Ben last year?
IrinaK [193]

Answer:

Ella grew \frac{1}{12} of an inch more

Step-by-step explanation:

For this problem, you want to subtract Ben's growth from Ella's.

This expression would be \frac{3}{4}-\frac{2}{3}.

To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).

In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by \frac{3}{3} and the second by \frac{4}{4}.

This makes the expression \frac{9}{12}-\frac{8}{12}, which equals \frac{1}{12}.

**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!

7 0
3 years ago
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