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Alex73 [517]
3 years ago
13

Identify the angle pair as adjacent, vertical, or neither. 3 and 5

Mathematics
1 answer:
deff fn [24]3 years ago
5 0

Given:

A figure.

To find:

Whether the pair of angle 3 and angle 5 is adjacent, vertical, or neither.

Solution:

Adjacent angle: If two angles are adjacent to each other, it means they have a common vertex, one common side and they are not overlapping each other, then they are called adjacent angles.

Vertical angles: If two lines intersect each other then the opposite angles are known an vertical angles.

From the given figure it is clear that the angle 3 and angle 5 are neither adjacent nor vertical angles.

Therefore, the correct option is B.

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Doss [256]

Answer:

64

Step-by-step explanation:

height of the hypotenuse:

\sqrt{60^2-36^2} = \sqrt{3600 - 1296} = \sqrt{2304} = 48

36 : height = height : x

36 : 48 = 48 : x

x= 48^2/36 = 64

7 0
3 years ago
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Please try and answer this ASAP ! Which point lies on the circle represented by the equation (x − 3)2 + (y + 4)2 = 62?
Alex787 [66]

Answer:

(3,-4)

Step-by-step explanation:

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What equation describes the circle that is centered at (8, 3) and has a radius of 9
Sloan [31]

Answer:

<h3> (x-8)²+(y-3)² = 81</h3>

Step-by-step explanation:

The general equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the centre of the circle

r is the radius

Given the centre (8, 3) and the radius of 9, the equation of the circle will be;

(x-a)²+(y-b)² = r²

(x-8)²+(y-3)² = 9²

(x-8)²+(y-3)² = 81

hence the required equation is  (x-8)²+(y-3)² = 81

5 0
3 years ago
Is this corrrecct??? answe quick!?​
jok3333 [9.3K]

Answer: x = 27

Step-by-step explanation:

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Find the vertices of the hyperbola. Enter the smallest coordinate first.
melisa1 [442]

Answer:

([-3], [0]), ([3], [0])

Step-by-step explanation:

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\dfrac{x^2}{9} - \dfrac{y^2}{49} = 1

The vertices of an hyperbola (of the form)  \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 are (± a, 0)

The given hyperbola can we presented in a similar form as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = \dfrac{x^2}{3^2} - \dfrac{y^2}{7^2} = 1

Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;

The vertices of the parabola are ([-3], [0]), ([3], [0]).

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3 years ago
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