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3 years ago

Pls help ASAP will mark Brainlyest!!

Mathematics

2 answers:

Alika [10]3 years ago

3 0

Answer:

312cm2

Step-by-step explanation:

Area of the triangles:

A =1/2bh

A=1/2(10*12) = 1/2*120=60.

There are two triangles. 60*2=120. 120 is the area of both triangles.

Area of the rectangle:

16*12=192.

120+192=312cm2

Setler79 [48]3 years ago

3 0

312.cm

Explanation: I had this question before I got 100. Please give Brainlyest

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Express sin M as a fraction in simplest terms

Debora [2.8K]

Remember: SOH-CAH-TOA

Sine (of an angle!) = opposite / hypotenuse

We're looking at angle M here, to find the sine of M. Looking from angle M, the side that is opposite is NO and the hypotenuse is MO.

sin(M) = NO / MO = NO / 13

We do not know NO, but we can use the Pythagorean theorem to find NO because this is a right triangle.

Pythagorean theorem: a^2 + b^2 = c^2

---a and b are legs of the triangle, c is the hypotenuse

12^2 + b^2 = 13^2

144 + b^2 = 169

b^2 = 25

b = 5

NO = 5

sin(M) = NO / MO = 5 / 13

Answer: sin(M) = 5 / 13

Hope this helps!

8 0

2 years ago

a large painting has a length of 18 inches and width of 12 inches. If each dimension is reduced by x inches to make the ratio of

KiRa [710]

Answer:

The value of x = 3.

Step-by-step explanation:

The ratio between length and width is given by:

$\frac{L}{W}=\frac{5}{3}$

Where:

L represents the new length
W represents the new width

Now, we know that each dimension is reduced by x inches, it means:

$L=18-x$

$W=12-x$

Then, we will have:

$\frac{18-x}{12-x}=\frac{5}{3}$

Finally, we just need to solve it for x.

$3(18-x)=5(12-x)$

$5x-3x=60-54$

$2x=6$

$x=3$

Therefore, the value of x = 3.

I hope it helps you!

3 0

3 years ago

for the function f(x) = –(x 1)2 4, identify the vertex, domain, and range. the vertex is (–1, 4), the domain is all real numbers

stira [4]

F(x) = -(x + 1)^2 + 4
Vertex = (-1, 4)
Domain is all real numbers.
Range is f(x) <= 4

8 0

3 years ago

Read 2 more answers

Find the midpoint of the segment with the following endpoints. (2,9) and (8,1)

vazorg [7]

Answer:

$\displaystyle (5,5)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Midpoint Formula: $\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

Point (2, 9)

Point (8, 1)

Step 2: Identify

(2, 9) → x₁ = 2, y₁ = 9

(8, 1) → x₂ = 8, y₂ = 1

Step 3: Find Midpoint

Simply plug in your coordinates into the midpoint formula to find midpoint

Substitute in points [Midpoint Formula]: $\displaystyle (\frac{2+8}{2},\frac{9+1}{2})$
[Fractions] Add: $\displaystyle (\frac{10}{2},\frac{10}{2})$
[Fractions] Divide: $\displaystyle (5,5)$

7 0

3 years ago

Field book of an agricultural land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is

jekas [21]

Answer:

Plot I area= 32.5cm²

Plot II area = 73.09cm²

Plot III area = 35cm²

Plot IV area = 54cm²

Total the area of Field = 194.59cm²

Step-by-step explanation:

The field is made up of four plots with different shapes. So we would find the area of the 4 shapes to get the area of the plots.

A question related to this can be found at brainly (question ID: 18861101)

Find attached the diagram

Given:

AC = 13cm

AE = 19cm

CF = DE = 7cm

AD = AE - DE

AD = 19-7 = 12cm

GF = 9cm, EH = 15cm

GH = 17cm

Plot I: A right angle triangle

Area = ½ × base × height

Base = CD, height = AD

Using Pythagoras theorem

CD = √(AC² - AD)²

CD = √(13² - 12²) = √(169-144)

CD = √25 = 5

Area = ½ × 5 ×13= 32.5

Area plot I = 32.5cm²

Plot II: An equilateral triangle

Area of the equilateral triangle = a²/4 ×(√3)

√3=1.73

a = side = AC

Area = (13)²/4 ×(√3) = 42.25 × 1.73 = 73.0925

Area of Plot II = 73.09cm²

Plot III: A rectangle

Area of a rectangle = length × width

length = 7cm

width = 5cm

Area of plot III = 7×5 = 35cm²

Plot IV: A trapezium

Area of trapezium = ½(base 1 + base2) × height

Base 1= FE = CD

Base 2= GH

To get height using diagram 2. When you draw the lines from the two points on base1, you would have 1 rectangle in the middle with the two triangles by the side.

We would apply Pythagoras theorem to find h in the two right angled triangles:

Hypotenuse ² = opposite ²+adjacent ²

1st ∆: 9² = h²+a²

h² = 81-a²

2nd ∆: 15² = h² + (12-a)²

225 = h² +144 - 24a+ a²

225-144 = h²-24a+ a²

Insert value for h² in the 2nd

81 = 81-a² - 24a + a²

24a = 81-81

a= 0

h² = 81-0²

h = √81 = 9

Area of trapezium = ½(5+7) × 9

= 6 × 9

Area of plot IV= 54cm²

Total the area of field = area of plot I + area of plot II + area of plot III +area of plot IV

= 32.5 + 73.09 + 35+ 54

Total the area of Field = 194.59cm²

3 0

3 years ago