Three consecutive integers have a sum of 45. Find the integers.
1 answer:
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Angles formed when two parallel are intersected by a common transversal include, corresponding, alternate interior and exterior, same-side interior, and vertically opposite angles
The correct option is Same–Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°
The reason the selection is correct is as follows:
The given angles are;
m∠1 = (30·x - 30)°. m∠5 = (40·x + 70)°
∠1, and ∠5, are located on the same side of the transversal and are both formed on the interior side of the parallel lines
Therefore, they are same–side interior angles
Same side interior angles theorem states that same side interior angles formed between parallel lines are supplementary
Therefore, we have;
m∠1 + m∠5 = 180°
Which gives;
(30·x - 30)° + (40·x + 70)° = 180°
(70·x + 40)° = 180°
70·x = 180° - 40° = 140°
m∠1 = (30·x - 30)° = (30 × 2 - 30)° = 30°
m∠1 = 30°
m∠5 = (40·x + 70)° = (40 × 2 + 70)° = 150°
m∠5 = 150°
The correct option is therefore;
Same-Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°
Learn more about parallel lines cut by a transversal here:
Answer:
0.7246 radians
Step-by-step explanation:
According to the Question,
Given that, a rectangle box has length 12 inches, width 15 inches, and a height of 17 inches
- The length of the base diagonal (d) can be found using the Pythagorean theorem on length and width:
d = √{ (12)² +(15)² } = √(144+225) = √369inches
- The tangent of the angle is the ratio of the height of the box to this length
Tan∅ = 17/√369
Taking the , we have
∅ = (17/√369) ≈ 0.7246 radians