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rosijanka [135]
4 years ago
7

What is the simplified form of √10000x^64 ? 5000x^32 5000x^8 100x^8 100x^32

Mathematics
2 answers:
denis23 [38]4 years ago
8 0

Answer:

Option (d) is correct.

\sqrt{10000x^{64}}=100x^{32}

Step-by-step explanation:

Given : Expression \sqrt{10000x^{64}}

We have to write a simplified form of the given expression \sqrt{10000x^{64}}

Consider the given expression \sqrt{10000x^{64}}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

=\sqrt{10000}\sqrt{x^{64}}

Factor 10000 as 10000=100^2

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

\sqrt{100^2}=100

also, \mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0

We have,

\sqrt{x^{64}}=x^{\frac{64}{2}}=x^{32}

Thus, \sqrt{10000x^{64}}=100x^{32}

Masja [62]4 years ago
4 0

Answer: D. 100x32

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
You're a manager in a company that produces rocket ships. Machine A and Machine B both produce cockpits and propulsion systems.
GalinKa [24]

Answer:

No you cannot.

Step-by-step explanation:

Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.

For Machine A, we have 4 cockpits; this would take 4c time.  We also have 6 propulsion systems; this would take 6p time.  Together it takes 26 hours; this would give us

4c+6p=26.

For Machine B, we have 8 cockpits; this would take 8c time.  We also have 12 propulsion systems; this would take 12p time.  Together it takes 56 hours; this would give us

8c+12p=56

This gives us the system

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To solve this, we want the coefficients of one of the variables to be the same.  To make the coefficients of c the same, we can multiply the top equation by 2:

\left \{ {{2(4c+6p=26)} \atop {8c+12p=56}} \right. \\\\\left \{ {{8c+12p=52} \atop {8c+12p=56}} \right.

To cancel c, we will subtract the second equation from the first one.  However, this also cancels p:

\left \{ {{8c+12p=52} \atop {-(8c+12p=56)}} \right. \\\\0+0=-4\\0=-4

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

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oksian1 [2.3K]

Answer:

The center is at (-3, -2) and the radius = 1.

Step-by-step explanation:

We can do this by converting the given equation to standard form.

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Completing the square on the x and y terms:

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So the center is (-3, -2) and the radius = 1.

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