For the answer to the question above,
<span>a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
c) Now use a = v² / r
where a was found above
and r was given
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given </span>
Step 1: simplify
[3.4 ( 6 x + 2 ) +3] + 4 p -3 x
Pemdas!
6x+2=8x
3.4+3=6.4
6.4+8x=14.4
14.4x+4p=18.4xp+3= 21.4xpx
x=8
p=18.4
Other x = 21.4
<span><span>D. Allow him or her to view data as an easy to understand image that might be recognized as a pattern and solved without costly data analysis.</span></span>
The Answer Is -54xy(9xy-2y^4+10x)
30x^7
Multiply the coefficients (6•5) to get 30, then add the exponents (4+3) to get 7
Hope this helps!
