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Varvara68 [4.7K]
3 years ago
12

Q6. The diagram shows that a ship sails 34 nautical miles from its port. Then after sailing 19 nautical miles due east, it is di

rectly north of the port. How far is the ship from the port?
​
Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

the answer is... it might be tricky but the answer is

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Solve to find x and y in the diagram.
lesantik [10]

15x = 90

   x = 6


5(6) + 12y = 90

30 + 12y = 90

12y = 60

  y = 5

Answer: 3rd option

x =6, y = 5

5 0
3 years ago
The answer to math problem
Degger [83]

<em>First, you would multiply 2 x 16. </em>

2 x 16 = 32

<em>Using that number, subtract by 8. </em>

32 - 8 = 24

<em>Multiply 3 x 16. </em>

3 x 16 = 48

<em>Subtract the two numbers from step 2 and 3. </em>

48 - 24 = 24


8 0
3 years ago
Please help ASAP <br><br> Find the exact value of : <br> log 1/1000
zzz [600]
Log base 10 (1/1000)
10^x = 1/1000
Log1/1000 = -3
4 0
4 years ago
Find the magnitude and direction of the vector JK given points J(1,0) &amp; K(-2,3)
Stella [2.4K]
Draw points J and K in the coordinate axis, and join them so that the top of the vector is point K.

the magnitude of the vector is just the length of the segment JK, so we can either write it as |JK| or |KJ|, it does not make any change.

Let O be the point in the x axis such that KO is perpendicular to OJ, as shown in the picture.

From the Pythagorean theorem: 

|KJ|= \sqrt{ |OK|^{2} + |OJ|^{2} } = \sqrt{3^{2} + 3^{2} } = \sqrt{2*3^{2}}=3 \sqrt{2} units

since |OK|=|OJ|, the right triangle KOJ is isosceles, so the measure of KJO is 45°, which means that the angle of vector JK to the positive x axis is 180°-45°=135°


Answer: magnitude=  3 \sqrt{2} units, direction : 135°

3 0
3 years ago
What is the sum of 10 and a number y is equal to 18
sveticcg [70]
Wouldn't it be 8? 10+8 would equal 18
6 0
3 years ago
Read 2 more answers
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