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fgiga [73]
3 years ago
13

Which one answer fast !

Mathematics
2 answers:
max2010maxim [7]3 years ago
6 0

Answer:

A, 1/4

0.25 simplified is 1/4, as shown in the diagram.

Montano1993 [528]3 years ago
5 0

Answer:

A is the correct answer to your question

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A diagram of miles skateboard is shown below its dimensions. Smiles plants to paint the ramp excluding the bottom what is the ar
Alex_Xolod [135]

Answer:

Step-by-step explanation:

area of ramp = 24 x 36= 864

area of side (square)= 24 x 24 = 576

area of 2-side (triangle)= 2 x (0.5 x 24 x 41.8) = 1003.2

total area to be painted = 864 + 576 + 1003.2 = 2443.2

4 0
3 years ago
The temperature of the rod was 10°C above zero. It was kept in a freezer at 2 p.m. If
aleksklad [387]

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I think it would take 6 minutes to reach temperature below 8 °C

5 0
2 years ago
Read 2 more answers
PLS HELP
Rzqust [24]
1+1=2!!

hope that helps
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3 years ago
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A school is having a canned food drive. Each class is challenged to collect 220 cans. If there are x classes in the school, whic
lara31 [8.8K]

Answer:

B)

Step-by-step explanation:

no. of Classes = x

cans = 220

220×x = 220x

no.of classes × cans = total number of cans

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2 years ago
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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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