Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
-2
Step-by-step explanation:
-4(3x – 7) = 52
3x-7= -13
3x= -6
x= -2
Generally speaking, the number of solutions to an algebraic equation is equal to the exponent of the highest power. so the answer is b.4
Answer:
Just multiply
length x width = area
94 x 50 = 4700
Step-by-step explanation:
Its 400 because 363 is closer to 400 than 300