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iragen [17]
3 years ago
15

Help me please I need the help

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

p - 3

Step-by-step explanation:

Key expression: 3 fewer than

Fewer than = subtract from

subtract 3 from a number, p

This means that the expression would be p - 3

Because you are subtracting 3 from a number ( p )

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Do the data in the table represent a direct variation or inverse variation? Write an equation to model the data in the table?
notsponge [240]

Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x

<h3>Variation</h3>

  • Direct variation

y = k × x

4 = k × 2

4 = 2k

k = 4/2

k = 2

when y = 2 and x = 4

y = k × x

= 2 × 4

y = 8

  • Indirect variation

y = k/x

4 = k / 2

8 = k

when y = 2 and x = 4

y = k/x

2 = k/4

2 × 4 = k

k = 8

So,

y = k/x

y = 8/x

Learn more about variation:

brainly.com/question/6499629

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5 0
2 years ago
Y is directly related to X, and Yis 81 when X is 27.<br> The constant of variation is
Arisa [49]

Answer:

3

Step-by-step explanation:

A direct variation is of the form

y = kx

We know x and y so we can find k

81 = k *27

Divide each side by 27

81/27 = 27k/27

3=k

The constant of variation is 3

5 0
4 years ago
Denise Rose the number cube that has sides labeled 1 to 6 and then flips a coin what is the probability that she rolls in odd nu
NARA [144]
1.36 percent chance hand ks
4 0
3 years ago
Please help me ASAP!!!<br> WILL MARK BRAINLIEEST TO WHOEVER IS RIGHT
konstantin123 [22]

Answer:

The answer is 5 x 2 x 3 x 2 x 2

Step-by-step explanation:

It is just everything at the bottom multiplied together

4 0
3 years ago
Read 2 more answers
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
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