You set up was almost accurate. Remember the arc length formula:
If f'(y) is continuous on the interval [a,b], then the length of the curve x = f(y), a ≤ y ≤ b should be;
L = ∫ᵇ ₐ √1 + [f'(y)]^2 * dy
We have to find the length of the curve given x = √y - 2y, and 1 ≤ y ≤ 4. You can tell your limits would be 1 to 4, and you are right on that part. But f'(y) would be rather...
f'(y) = 1/(2√y) - 2
So the integral would be:
∫⁴₁ √1 + (1/(2√y) - 2)² dy
Using a calculator we would receive the solution 5.832. Their is a definite curve, as represented below;
Answer:
<h2>
13/14 > 25/28 </h2>
Step-by-step explanation:
Given the inequalities 13/14 > 25/28, 21/25 < 4/9, 5/6>11/12, 4/5< 8/25, in order to know which of the statement is true, we have to simply solve each of the inequality as shown
We will have to convert all then fractions to decimals because It is quite difficult to ascertain the true statement with fraction.
for 13/14 > 25/28
0.93 > 0.89
21/25 < 4/9,
For 0.84< 0.44
This statement is not true because 0.84 us greater than 0.44 not less than 0.44
for 5/6>11/12, this is equivalent to 0.83>0.92. This statement is also false because 0.83 is less than 0.92 not greater than 0.92
For 4/5< 8/25, this is also similar to 0.8<0.32. This statement is also false because 0.8 is greater than 0.32 not less than 0.32
From the above calculation, only 13/14 > 25/28 is the true statement
Answer:
Step-by-step explanation:
area of sector = angle/360 * pi * r^2
59.4 = angle/360 * 3.142 * 17.9^2
angle = 21.24
