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2 years ago

There are 17 boxes each box holds 42. how many packets of sweets are there in total?

Mathematics

2 answers:

Leto [7]2 years ago

4 0

Answer:

No.of sweets in one box = 42

No.of sweets in 17 boxes = 42 x 17

= 714

Citrus2011 [14]2 years ago

3 0

Answer: 714

Step-by-step explanation:

42 • 17 = 714

divide to check if it is correct

714 ÷ 42 = 17 or 714 ÷ 17 = 42

hope it helps!

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If the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g?

MArishka [77]

Answer: B. -3 and 7

Step-by-step explanation:

To find the zeros, just move the constants to the other side,

x - 7 ⇒ x = 7

x + 3 ⇒ x = -3

If the number is moved to the other side its sign becomes opposite

Hope it helps!

8 0

2 years ago

A card isn’t drawn from a standard 52 card deck (no jokers) Mach each event with it’s probability

timofeeve [1]

We can't match events with probability if there is no events... do you have the events?

7 0

3 years ago

Where might you see the double of 5 in real life

ira [324]

Answer:

Your eyes: 1+1, Legs of a dog: 2+2, Your fingers: 5+5, Etc.

Step-by-step explanation:

4 0

2 years ago

Suppose that Bob leaves a job that pays $100,000 per year in order to open a new sponge business. His insurance cost is $8,000,

tensa zangetsu [6.8K]

Answer:

-$11,000 is the economic profit or we can say it is a loss.

Step-by-step explanation:

The job paid Bob = $100000

The insurance cost is = $8,000

The material cost is = $15,000

The lease payments are = $8,000

The sales revenue is $120,000.

So, Bob's economic profit is: $120000-100000-8000-15000-8000=-11000$

Therefore, his economic profit is -$11000.

5 0

3 years ago

Determine all critical points the the function:

romanna [79]

$\bf y=x^2-32\sqrt{x}\implies \cfrac{dy}{dx}=2x-32\cdot \cfrac{1}{2}x^{-\frac{1}{2}}\implies \cfrac{dy}{dx}=2x-\cfrac{32}{2\sqrt{x}}
\\\\\\
\cfrac{dy}{dx}=2x-\cfrac{16}{\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{2\sqrt{x^3}-16}{\sqrt{x}}\\\\
-----------------------------\\\\$

$\bf 0=\cfrac{2\sqrt{x^3}-16}{\sqrt{x}}\implies 0=2\sqrt{x^3}-16\implies 16=2\sqrt{x^3}
\\\\\\
8=\sqrt{x^3}\implies 2^3=\sqrt{x^3}\implies (2^3)^2=x^3\implies (2^6)^{\frac{1}{3}}=x
\\\\\\
2^{\frac{2}{1}}=x\implies \boxed{4=x}\\\\
-----------------------------\\\\
\textit{the other critical point at }\sqrt{x}=0\implies \boxed{x=0}$

7 0

2 years ago