Compute the dimensions of gravitational constant G where F=Gm1m2/r^2
1 answer:
Answer:
G=L^3/(T^2M)
Step-by-step explanation:
- G=(Fr^2)/Mm
- G=(ML^3)/(T^2M^2)
- G=L^3/(T^2M)
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Answer:
Step-by-step explanation:
perp. 4/3
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Answer:
a = 17
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Answered by GAUTHMATH
<span>W=15 & L=25
character requirement
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