Compute the dimensions of gravitational constant G where F=Gm1m2/r^2

Mathematics

1 answer:

VARVARA [1.3K]2 years ago

8 0

Answer:

G=L^3/(T^2M)

Step-by-step explanation:

G=(Fr^2)/Mm
G=(ML^3)/(T^2M^2)
G=L^3/(T^2M)

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Find the substance's half-life, in days.<br> Round your answer to the nearest tenth.

shutvik [7]

Answer:

t = 5.6 day

t =5 days 14 hours 24 minutes

Step-by-step explanation:

Half life is the time it will take for the original value or quantity I'd a particular substance to decrease by half of it's original self.

N = N•e(-kt)

N• = 25

K = 0.1229

Then

N = 25/2 = 12.5

The reason because at the half life , it's original value will decrease to half.

Let's solve for the half life t

N = N•e(-kt)

12.5 = 25e(-0.1229t)

12.5/25 = e(-0.1229t)

0.5 = e(-0.1229t)

In 0.5 =-0.1229t

-0.69314 = -0.1229t

-0.69314/-0.1229 = t

5.6399 = t

To the nearest tenth

5.6 days = t

4 0

3 years ago

Which graph shows the line y - 2 = 2(x + 2)?

klasskru [66]

For this case we have the following linear function:
$y - 2 = 2 (x + 2)
$
Rewriting we have:
$y - 2 = 2x + 4

y = 2x + 4 + 2

y = 2x + 6$
We observe that the linear function has:
Positive slope and equal to 2.
Intersection with the axis y equal to 6.
Answer:
y = 2x + 6
See attached image