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Alexxandr [17]
2 years ago
5

Mary saved her money

Mathematics
1 answer:
Murrr4er [49]2 years ago
4 0
130 if you round that to the nearest whole number then you’ll get 139
You might be interested in
Very easy math question
charle [14.2K]

Answer:

C. 179 ft²

Step-by-step explanation:

Area of circular path or walkway

= π × (R + r) × width

Where

R= Outer radius

r = Inner Radius

Diameter = 16 feet

Width = 3 feet

Inner Radius = Diameter/2

= 16 feet/2 = 8 feet

Outer Radius = 8 + 3 = 11 ft

Hence:

= π × (11 + 8) × 3

= π × 19 × 3

= 179.07078125 ft²

Approximately = 179 ft²

The area of the circular walkway = 179ft²

Option C is correct.

7 0
3 years ago
What is an angle that is complementary to DGE?<br><br> (Please hell I’ll reward)
weqwewe [10]

Answer:

<CGD

Step-by-step explanation:

Since m<CGB = right angle = 90°, therefore:

m<CGE = 90° (linear pair angles)

Complementary angles add up to 90°.

Thus, m<CGD + m<DGE = m<CGE = 90°.

Therefore, the angle that is complementary to <DGE is <CGD

3 0
3 years ago
Pattern for add 11 subtract 6
Dahasolnce [82]
The answer is 5 11-6=5
6 0
3 years ago
Helpp!!!!!!!!!!!!!!!!!!
nekit [7.7K]
I think it’s X+12=-15
6 0
2 years ago
Read 2 more answers
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
Read 2 more answers
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