To find the answer to that, you have to see how many numbers are between 13 and 31. There are 18 numbers between 13 and 31. Divide 18 by 2 and you will get the number halfway. 9 is halfway between 13 and 31. So, add 9 to 13 and you get 22.
The answer is 22.
Hope I helped
Answer:
Look at the image.
Step-by-step explanation:
the radius is d/2. r=41/2 r=20.5
Step-by-step explanation:
Using the Poisson distribution, it is found that there is a 0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.
<h3>What is the Poisson distribution?</h3>
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

The parameters are:
- x is the number of successes
- e = 2.71828 is the Euler number
is the mean in the given interval.
Considering the average of 15 birds every 2 hours during daylight hours, the mean for a 45-minute period is given by:

The probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours is given by:

In which:







Then:

0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.
More can be learned about the Poisson distribution at brainly.com/question/13971530
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