Answer:
D. 4
Step-by-step explanation:
Percent of drivers who wear seat belts = 68
Percent of drivers who do not wear seat belts = 100 - 68 = 32
Now, we know that for every 100 pull overs, 32 drivers will not be wearing belt.
32 drivers without seat-belt = 100 pullovers
1 driver without seat-belt = 100/32 pullovers
1 driver without seat-belt = 3.125 pullovers (4 pullovers)
So, a police officer should expect 4 pullovers until she finds a driver not wearing a seat-belt.
Answer:
As per the given statement: when the lights go out at the store at night there's a 15% off sign hanging out by the make up counter.
To find the number as a decimal and a fraction in simplest form.
Given the Number = 15%.
If we convert any number from percent to decimal divide by 100 and remove the % sign.
Then the given number in decimal is, 0.15
Now, to convert this percent into fraction;
Divide both numerator and denominator by 5 to get;
Therefore, the given number in fraction is; 
171 is rounded to 200 as it is closest to 200 than 100
and 727 is rounded to 700 as it is closest to 700 than 800
when we add 200 and 700 we get the answer 900
The sum of 171 and 727 is:
171 + 727 = 898
and 898 is rounded to 900 as it is closest to 900 than 800.
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
314.16cm²
Step-by-step explanation:
