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Monica [59]
3 years ago
7

A man saved N48 000 with a cooperative

Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Answer:

N5760

(48000x4x3) ➗ 100=N5760

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Solve 5(8x + 4) = 300 . PLEASE HELP ME IT'LL MAKE MY DAY​
pentagon [3]
X=7 5x8 is 40x and 5x4 is 20 take away 20 from both sides so it looks like this 40x=280 then divide by 40
3 0
3 years ago
A peach pie baked from 12:46 until 1:24 pm how long did the pie bake
Sergio039 [100]

Answer:

The peach pie baked for 38 minutes

Explanation: there are 60 minutes in an hour.

so adding 14 mins to 12:46 would give us 1:00. then adding 24 minutes to that gives us 1:24.    14+24 =38

7 0
3 years ago
Find the range of the following piecewise function.
mash [69]

Answer:

\huge\boxed{[-5;\ -2)\ \cup\ [3;\ 13)}

Step-by-step explanation:

The following piecewise functions are linear functions. The graph of any of them is a line segment.

We just need to calculate the value of the function at each end specified in the brace.

y=3x-2\ \text{if}\ -1\leq x

Substitute x =-1 and x = 0:

x=-1\\y=3(-1)-2=-3-2=-5\\\\x=0\\y=3(0)-2=0-2=-2

Range of this piece is [-5; -2)

y=2x+3\ \text{if}\ 0\leq x

Substitute x =0and x = 5:

x=0\\y=2(0)+3=0+3=3\\\\x=5\\y=2(5)+3=10+3=13

Range of this piece is [3; 13)

Therefore the range of the following piecewise function is:

[-5;\ -2)\ \cup\ [3;\ 13)

Look at the picture.

6 0
3 years ago
HELP PLEASEEE ASAP ! THANK YOU :)
Salsk061 [2.6K]

Answer:

f(x) = 2x³ - 6x² - 48x + 24

relative minimum: (4,-136)

relative maximum: (-2,80)

answer is the second option

6 0
4 years ago
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In physics, if a moving object has a starting position at s 0, an initial velocity of v 0, and a constant acceleration a, then t
stiks02 [169]
Actually the position function with respect to time under constant acceleration is:

a=g

v=⌠g dt

v=gt+vi

s=⌠v

s=gt^2/2+vit+si

So if vi and si are zero then you just have:

s=gt^2/2

Notice that it is not gt^2 but (g/2) t^2

So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...

Anyway....

sf=(a/2)t^2+vit+si

(sf-si)-vit=a(t^2)/2

2(sf-si)-2vit=at^2

a=(2(sf-si)-2vit)/t^2  and if si and vi equal zero

a=(2s)/t^2

8 0
3 years ago
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