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2 years ago

What is the area of the object above? (Picture Attached :D)

Mathematics

2 answers:

Natali5045456 [20]2 years ago

8 0

(8 • 12) + (6 • 5)

Hopefully you can get the rest!

Alina [70]2 years ago

7 0

Answer:

<u>126</u> <u>in.</u>

Step-by-step explanation:

12*8 = 96

5*6 = 30

96 + 30 = 126

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Estimate 58,088-39,625 by first rounding each number to the nearest thousand.

Tpy6a [65]

Answer:

Here is the answer, I took it as simple I could.

7 0

2 years ago

Identify the coordinates of the vertices of each figure after the similarity transformation.

bija089 [108]

Answer:

After translation:

Translation: (x, y) → (x-6, y-8)

W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

After dilation:

Dilation: (x, y) → (2x, 2y), centered at (0, 0)

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

Step-by-step explanation:

Given the vertices of the Quadrilateral WXYZ

W(-4, 8)

X(-4, 0)

Y(-12, 4)

Z(-8, 16)

As the rule of translation is given by

Translation: (x, y) → (x-6, y-8)

So, after the translation the vertices of Quadrilateral WXYZ will be translated as:

W(-4, 8) → (x-6, y-8) ⇒ (-4-6, 8-8) = W'(-10, 0)

X(-4, 0) → (x-6, y-8) ⇒ (-4-6, 0-8) = X'(-10, -8)

Y(-12, 4) → (x-6, y-8) ⇒ (-12-6, 4-8) = Y'(-18, -4)

Z(-8, 16) → (x-6, y-8) ⇒ (-8-6, 16-8) = Z'(-14, 8)

Therefore,

W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

Next, the rule of dilation is given by

Dilation: (x, y) → (2x, 2y), centered at (0, 0)

W'(-10, 0) → (2x, 2y) ⇒ (2(-10), 2(0)) = W'' (-20, 0)

X'(-4, 0) → (2x, 2y) ⇒ (2(-4), 2(0)) = X'' (-8, 0)

Y'(-12, 4) → (2x, 2y) ⇒ (2(-12), 2(4)) = Y'' (-24, 8)

Z'(-8, 16) → (2x, 2y) ⇒ (2(-8), 2(16)) = Z'' (-16, 32)

Therefore,

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

8 0

2 years ago

Use the graph of the function to find, f(-6)

kati45 [8]

Answer:

f(-6) = 3

Step-by-step explanation:

In order to find the value of f(-6), we need to find what y-value appears associated with x = -6 according to the graph resented.

Therefore, go to x = -6 on the horizontal axis (six units to the left of the origin of the coordinate system), and find at what value of the y-axis the vertical grid passing through x = -6 intercepts the graph of the function.

That is indicated by a red dot in the attached image.

We see therefore that for x = -6 the y-value that the graph of the function shows in the vertical scale is "3".

Then, f(-6) = 3

5 0

3 years ago

A stereo is marked down $75. If this is a 15% decrease, what was the original price for the stereo?

g100num [7]

The original price was $500
First we find 15% of what is $75
15/100 x N =$75
n = $7500/15
n = $500

5 0

2 years ago

a train travels 288km at a uniform speed.if the speed has been 4km per hour more it would have taken one hour less for the same

Lostsunrise [7]

Given:

A train travels 288 km at a uniform speed.

If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

To find:

The initial speed of the train.

Solution:

Let x km/h be the initial speed on the train.

New speed of train = (x+4) km/h

We know that,

$Time=\dfrac{Distance}{Speed}$

Time taken by the train initially to cover 288 km is $\dfrac{288}{x}$ hours.

New time taken by the train to cover 288 km is $\dfrac{288}{x+4}$ hours.

It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

$\dfrac{288}{x}-\dfrac{288}{x+4}=1$

$\dfrac{288(x+4)-288x}{x(x+4)}=1$

$288x+1152-288x=x^2+4x$

$1152=x^2+4x$

$0=x^2+4x-1152$

Splitting the middle term, we get

$x^2+36x-32x-1152=0$

$x(x+36)-32(x+36)=0$

$(x+36)(x-32)=0$

$x=-36,32$

We know that the speed cannot be negative. So, the only possible value of x is 32.

Therefore, the speed of the train is 32 km/h.

3 0

2 years ago