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mixer [17]
3 years ago
5

Jans age is 3 years less than twice trays age. the sum of there age is 30 find the ages please

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0
You must use ALGEBRA in order to solve this problem.

Step 1. T= Tray's age and J= Jan's age
Step 2. (T*2)-3 and T+J=30
Step 3. Tray must be 11 because and Jan must be 19, it never said that Tray is OLDER. 
Step 4. Recheck----- (11*2)-3=19

Sorry, I don't explain too well, I am used to doing it in my head... Hope this helps!!! :D
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A basketball player has 45 steals, 72 assists, 90 rebounds, and 432 points. What is
aalyn [17]

Answer:

5:24

Step-by-step explanation:

We're provided with the number of rebounds as 90 while the points are 432. Expressing them into ratio of rebounds to steals we have

90:432

Simplification:

Dividing both sides by 2 we obtain

45:216

Dividing both sides of the above ratio by 3 we obtain

15:72

Dividing both sides of the above ratio further by 3 we obtain

5:24

Therefore, rhe simplified ratio of rebounds ro steals is 5:24

8 0
3 years ago
All of the following are equivalent except...
Pie

Answer:

d) 11x^2 because that would be the same as 11x * 11x

6 0
2 years ago
Type the correct answer in each box. If necessary, use / for the fraction bar(s).
Tom [10]

Given:

The values are a=0.\overline{6},b=0.75.

To find:

The values of ab and \dfrac{a}{b}.

Solution:

We have,

a=0.\overline{6}

a=0.666...                     ...(i)

Multiply both sides by 10.

10a=6.666...                 ...(ii)

Subtracting (i) from (ii), we get

10a-a=6.666...-0.666...

9a=6

a=\dfrac{6}{9}

a=\dfrac{2}{3}

And,

b=0.75

b=\dfrac{75}{100}

b=\dfrac{3}{4}

Now, the product of a and b is:

ab=\dfrac{2}{3}\times \dfrac{3}{4}

ab=\dfrac{1}{2}

The quotient of a and b is:

\dfrac{a}{b}=\dfrac{\dfrac{2}{3}}{\dfrac{3}{4}}

\dfrac{a}{b}=\dfrac{2}{3}\times \dfrac{4}{3}

\dfrac{a}{b}=\dfrac{8}{9}

Therefore, the required values are ab=\dfrac{1}{2} and \dfrac{a}{b}=\dfrac{8}{9}.

6 0
3 years ago
A man bought 42 stamps, some 13¢ and some 18¢. How many of each kind did he buy if the cost was $6.66?
OverLord2011 [107]
Let's call the 13¢ stamps a and the 18¢ stamps b: a+b = 42 and therefore a= 42-b (formula 1) 0.13a+0.18b= 6.66 In this formula, substitute the value of a according to formula 1: 0.13(42-b)+0.18b= 6.66 Multiply on the left to get rid of the parenthesis: 5.46-0.13b+0.18b= 6.66 Subtract 5.46 from both sides: -0.13b+0.18b= 1.20 Add on the left: 0.05b= 1.20 Divide both sides by 0.05 b= 24 You have 24 18¢ stamps and: 42-24= 18 13¢ stamps Check: (24 x 0.18) + (18 x 0.13)= 6.66 Correct.
5 0
3 years ago
16=5a+a<br> Helppp please
Nostrana [21]
A=8/3

5a+a= 6a

16/6a= 8/3
3 0
3 years ago
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