All categories

3 years ago

How do I work this out?

Mathematics

2 answers:

Crank3 years ago

8 0

Answer:

$503.90

Step-by-step explanation:

6500 X .93= 6045

6045/12=503.90

ehidna [41]3 years ago

8 0

Answer:

503.75

Step-by-step explanation:

7% of 6500=

6045

divide by 12 because you have pay the full balance in 12 monthly payments =503.75

You might be interested in

Which is the best definition of an exterior angle of a triangle

Nina [5.8K]

Answer:

exterior of an angle should add up to 180 with the other angle. so the angle next to the exterior angle should add up to 180. the exterior angle should be the one outside or facing the or opening up to the outside.

Step-by-step explanation:

5 0

4 years ago

Identify the y-intercept of the function, f(x) = -x2 + 3x + 5.

Gennadij [26K]

Answer:

(0,5)

Step-by-step explanation:

when x=0። y=5

i guess

7 0

2 years ago

Read 2 more answers

Hello again! This is another Calculus question to be explained.

podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions

Function Notation

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the following and are trying to find the second derivative at x = 2:

$\displaystyle f(2) = 2$

$\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}$

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

$\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}$

When we differentiate this, we must follow the Chain Rule: $\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]$