Question

write the standard form of the equation of the circle with the given center and radius (6,4), r= square root of 7

Answer 1

The standard form of the equation of a circle is $(x-6)^{2}+(y-4)^{2}=7$.

Solution:

Center of the circle = (6, 4)

Radius of the circle = $\sqrt{7}$

To find the equation of the circle:

General formula for the equation of a circle

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where (h, k) is the center of the circle and r is the radius of the circle.

Here, h = 6, k = 4 and r = $\sqrt{7}$

$(x-6)^{2}+(y-4)^{2}=(\sqrt{7}) ^{2}$

$(x-6)^{2}+(y-4)^{2}=7$

Hence the standard form of the equation of a circle is $(x-6)^{2}+(y-4)^{2}=7$.