Hi there!
We can begin by simplifying cos(a + b) to find an equivalent expression.
With a sum of angles identity for cosine, we can determine that:
cos(a + b) = cos(a)cos(b) - sin(a)sin(b)
In this instance, we have to multiply this expression by csc(a)csc(b). Therefore:
(csc(a)csc(b)) · (cos(a)(cos(b) - sin(a)sin(b))
Distribute:
(csc(a)(csc(b))(cos(a)(cos(b)) - (csc(a)csc(b))(sin(a)sin(b))
Rewrite csc as 1/sin to simplify:
(1/sin(a) * 1/sin(b))(cos(a)(cos(b)) - (1/sin(a) * 1/sin(b))(sin(a)sin(b))
Multiply:
cos(a)/sin(a) * cos(b)/sin(b) - 1/sin(a) * sin(a) * 1/sin(b)*sin(b) <--- = 1
We now have remaining:
cos(a) / sin(a) * cos(b)/sin(b) - 1
Simplify to cotangent:
cot(a) * cot(b) - 1
The answer is d=<span>= 1/2 (a+b) 2nd power </span>
Answer:
150 cans were thrown away
Step-by-step explanation:
If the weight of 10 aluminum cans=0.16 kilogram
Each can weighs=0.16 kilograms/10
=0.016kg per can
If the family threw away 2.4 kilogram of aluminum in a month,
How many cans did they throw away?
Total cans thrown away= Total kilogram of cans/each kilogram of cans
=2.4kg/0.016kg
=150 cans
150 cans were thrown away
To determine the length of time it would took for the biker to cool down, we need the rate that would relate the distance he traveled to cool down per units of time. For this problem, the rate is given as 0.25 miles per minute. So, we simply divide the total distance he traveled with this rate. We calculate as follows:
time to cool down = distance / rate
time to cool down = 35 miles / 0.25 miles / minute
time to cool down = 140 minutes or 2 hrs and 20 minutes
Therefore, the biker would need to cool down for about 2 hrs and 20 minutes if he traveled for 35 miles.
Answer:ME PLease
Step-by-step explanation: