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3 years ago

write the standard form of the equation of the circle with the given center and radius (6,4), r= square root of 7

Mathematics

1 answer:

REY [17]3 years ago

3 0

The standard form of the equation of a circle is $(x-6)^{2}+(y-4)^{2}=7$ .

Solution:

Center of the circle = (6, 4)

Radius of the circle = $\sqrt{7}$

To find the equation of the circle:

General formula for the equation of a circle

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where (h, k) is the center of the circle and r is the radius of the circle.

Here, h = 6, k = 4 and r = $\sqrt{7}$

$(x-6)^{2}+(y-4)^{2}=(\sqrt{7}) ^{2}$

$(x-6)^{2}+(y-4)^{2}=7$

Hence the standard form of the equation of a circle is $(x-6)^{2}+(y-4)^{2}=7$ .

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Simplify the expression 3/2 (5/3) -1 1/4 + 1/2 Given the answer as a simplified fraction. The simplified expression is a/b.

ella [17]

<h2>Hello!</h2>

The answer is:

The simplified fraction is:

$\frac{7}{4}$

To solve this problem we must remember the following:

- Addition or subtraction of fractions, we add or subtract fractions by the following way:

$\frac{a}{b}(+-)\frac{c}{d}=\frac{ad(+-)bc}{bd}$

- Product of fractions, the multiplication of fraction is linear, meaning that we should multiply the numerator by the numerator and denominator by denominator, so:

$\frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}$

- Convert mixed number to fraction,

$a\frac{b}{c}=a+\frac{b}{c}=\frac{ac+b}{c}$

So, solving we have:

$\frac{3}{2}*\frac{5}{3}-1\frac{1}{4}+\frac{1}{2}=\frac{3*5}{2*3} -1\frac{1}{4}+\frac{1}{2}\\\\\frac{3*5}{2*3} -1\frac{1}{4}+\frac{1}{2}=\frac{15}{6} -1\frac{1}{4}+\frac{1}{2}\\\\\frac{15}{6} -1\frac{1}{4}+\frac{1}{2}=\frac{15}{6} -(1+\frac{1}{4})+\frac{1}{2}\\\\\frac{15}{6} -(1+\frac{1}{4})+\frac{1}{2}=\frac{15}{6}-(\frac{4+1}{1*4})+\frac{1}{2}\\\\\frac{15}{6}-(\frac{4+1}{4})+\frac{1}{2}=\frac{15}{6}-\frac{5}{4}+\frac{1}{2}$

$\frac{15}{6}-\frac{5}{4}+\frac{1}{2}=(\frac{5}{2}-\frac{5}{4})+\frac{1}{2}\\\\(\frac{5}{2}-\frac{5}{4})+\frac{1}{2}=(\frac{(4*5)-(2*5)}{8})+\frac{1}{2}\\\\(\frac{(4*5)-(2*5)}{8})+\frac{1}{2}=(\frac{20-10}{8})+\frac{1}{2}\\\\(\frac{20-10}{8})+\frac{1}{2}=(\frac{10}{8})+\frac{1}{2}\\\\(\frac{10}{8})+\frac{1}{2}=\frac{5}{4}+\frac{1}{2}\\\\\frac{5}{4}+\frac{1}{2}=\frac{(5*2)+(4*1)}{2*4}\\\\\frac{(5*2)+(4*1)}{2*4}=\frac{10+4}{8}=\frac{14}{8}\\\\\frac{14}{8}=\frac{7}{4}$

Hence, the simplified fraction is:

$\frac{7}{4}$

Have a nice day!

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Answer:

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Step-by-step explanation:

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