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Andreyy89
3 years ago
11

write the standard form of the equation of the circle with the given center and radius (6,4), r= square root of 7

Mathematics
1 answer:
REY [17]3 years ago
3 0

The standard form of the equation of a circle is (x-6)^{2}+(y-4)^{2}=7.

Solution:

Center of the circle = (6, 4)

Radius of the circle = \sqrt{7}

<u>To find the equation of the circle:</u>

General formula for the equation of a circle

(x-h)^{2}+(y-k)^{2}=r^{2}

where (h, k) is the center of the circle and r is the radius of the circle.

Here, h = 6, k = 4 and r = \sqrt{7}

(x-6)^{2}+(y-4)^{2}=(\sqrt{7}) ^{2}

(x-6)^{2}+(y-4)^{2}=7

Hence the standard form of the equation of a circle is (x-6)^{2}+(y-4)^{2}=7.

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