Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
Answer:
29
Step-by-step explanation:
In a parallelogram opposite angles are congruent, that means:
Angle L = Angle N, replace L & N by they respective value, then
3x-25 = 2x-10 ==> x=15 , Now plug the value of x in any of the 2 sides
3(15) -25 =20°
hence Angle L =- Angle N = 20°
Now let's calculate Angle M. In a parallelogram the adjacent angle are supplementary, that means their sum = 180°, then
Angle N + Angle N = 180°==> Angle M = 180°-20° = 160°
Answer:
a = 35
c = 85
Step-by-step explanation:
85 + 60 + a = 180 as they are all supplementary angles (together they form an angle of 180°)
therefore a = 35.
a + ( 180 -(a+85)) + c =180 (as the angles of a triangle add up to 180°. our triangle is NMT, the angles are a, c and 180°-(a+85°) for a theorem about lines secant to parallel lines)
therefore c = 85
(400-300)/300 x 100 = 100/300 x 100 = 33.33% increase
