This equation cannot be factored because its roots are irrational (as shown by solving with the quadratic formula). Also, to factor a quadratic equation, you need to find a pair of numbers whose product is equal to the c term (-5) and whose sum is equal to the b term (-6). There is no pair of numbers which satisfies this, further showing that the equation cannot be factored.

<u>Quadratic Formula:</u>

The quadratic formula is x= $\frac{-b ± \sqrt{b^{2}-4ac } }{2a}$ .

First, you need to find the a, b and c terms of your equation. They are 1, -6, and -5 respectively.

Now, you must plug in to the equation and solve for x. You must do so twice, once with a plus sign in the numerator and once with a minus.

$\frac{6 ± \sqrt{(-6)^{2}-4(1)(-5) } }{2(1)} \\\frac{6 ± \sqrt{36+20} }{2} \\\frac{6 ± \sqrt{56} }{2} \\\ \frac{6 ± 2\sqrt{14} }{2} \\3+\sqrt{14} \\3-\sqrt{14}$

The answers are 3+√14 and 3-√14.

Hope this helps!!

3 0

2 years ago

Two supplementary angles differ by 48°. find the angles.

OleMash [197]

this will need 2 equations, x+y=180 and x-48=y, this will make the answer be 114 and 66.

4 0

2 years ago