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mamaluj [8]
2 years ago
12

What is the surface area of this pyramid?

Mathematics
1 answer:
Grace [21]2 years ago
8 0

Answer:

Surface area of the given pyramid = 386.16 cm²

Step-by-step explanation:

Surface area of the given pyramid = Area of the square base + Area of the lateral sides

Area of the square base = (Side)²

                                        = (12)²

                                        = 144 cm²

Area of the lateral side = \frac{1}{2}(\text{Base})(\text{Lateral height})

Lateral height of the triangle = \sqrt{6^2+(9.1)^2} [By applying Pythagoras theorem]

                                                = \sqrt{82.81+36}

                                                = \sqrt{118.81}

                                                = 10.9 cm

Area of the lateral side = \frac{1}{2}(12)(10.9)

                                      = 60.54 cm²

Surface area of the given pyramid = Area of the base + 4(Area of one lateral side)

                                                          = 144 + 4(60.54)

                                                          = 144 + 242.16

                                                          = 386.16 cm²

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