Question

How do you solve this equation:\frac{(2a-2b)^2}{a-b}" alt="\frac{(2a-2b)^2}{a-b}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

4a-4b

Step-by-step explanation:

In the numerator, we can simplify this: (2a-2b)^2 = ((2)(a-b))^2 = (2)^2(a-b)^2 = 4(a-b)^2 = 4 (a-b)(a-b). Thus, we get: (4(a-b)(a-b))/(a-b). We can cancel the top and bottom with a-b and get: 4(a-b) = 4a-4b.

I hope this helps!