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Levart [38]
3 years ago
14

How do you solve this equation:

\frac{(2a-2b)^2}{a-b}" alt="\frac{(2a-2b)^2}{a-b}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

4a-4b

Step-by-step explanation:

In the numerator, we can simplify this: (2a-2b)^2 = ((2)(a-b))^2 = (2)^2(a-b)^2 = 4(a-b)^2 = 4 (a-b)(a-b). Thus, we get: (4(a-b)(a-b))/(a-b). We can cancel the top and bottom with a-b and get: 4(a-b) = 4a-4b.

I hope this helps!

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Vaselesa [24]

Answer:

1/3

Step-by-step explanation:

(1/3)^2x(1/3)^-1

so, we can write this as:

1/3 x 1/3 x 3/1

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There is also an easier way to do this,

(1/3)^2 x (1/3)^-1

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7 0
3 years ago
6-8x=7x-10x-24 solve for x
lana66690 [7]

Answer:

x = 6

Step-by-step explanation:

Let's solve your equation step-by-step.

6−8x=7x−10x−24

Step 1: Simplify both sides of the equation.

6−8x=7x−10x−24

6+−8x=7x+−10x+−24

−8x+6=(7x+−10x)+(−24)(Combine Like Terms)

−8x+6=−3x+−24

−8x+6=−3x−24

Step 2: Add 3x to both sides.

−8x+6+3x=−3x−24+3x

−5x+6=−24

Step 3: Subtract 6 from both sides.

−5x+6−6=−24−6

−5x=−30

Step 4: Divide both sides by -5.

−5x/-5 = -30 /-5

x=6

4 0
3 years ago
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