
<h3>x = 21/5</h3>
Step-by-step explanation:
<h3>___________________________</h3>
<h3>Given →</h3>
5x:9 = 7:3
<h3>So,</h3>
→ 5x/9 = 7/3
→ x = (7 × 9)/(3 × 5)
→ x = 21/5
<h3>___________________________</h3>
<h3>Hope it helps you!!</h3>
Answer:
D = 4, Z = 24
Step-by-step explanation:
6D+3Z = 96
5D+4Z = 116
multiply top by 5 and bottom by -6
top equation = 30D+15Z = 480
bottom equation = -30D-24Z = -696
Cancel 30D and -30 D
top equation = 15Z = 480
Bottom equation = -24Z = -696
15Z - 24 Z = 480 - 696
-9Z = 216
Z = 216/9
Z = 24
Now that we have the value of Z, we can substitute it in any equation to find D
6D + 3(24) = 96
6D + 72 = 96
6D = 96 - 72
6D = 24
D = 24/6
D = 4
Answer:
4.2
Step-by-step explanation:
4.1553
15 -> 2
4.2
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155

OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.