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LenKa [72]
3 years ago
7

A bag of marbles contains 5 red, 3 blue, 2 green, and 2 yellow marbles,

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

5/12 for red and 2/12 for green

multiple both 10/144

the answer is B 5/72

Step-by-step explanation:

You might be interested in
How many times larger is 3.6 x 106 than 7.2 x 105?
Kazeer [188]
- 374.4 is the answer


Explanation

3.6 * 106 = 381.6

7.2 * 105 = 756

Subtract 756 from 381.6
= - 374.4


Hope this helps :)

Have a great day !
4 0
3 years ago
Aisle 2 of a furniture store stocks 4-legged chairs, 4-legged tables, and 3-legged stools. If there are t tables, c chairs, and
maxonik [38]
4c + 4t + 3s = total number of legs

example : Lets say u have 3 chairs (c) and 2 tables (t) and 4 stools (s)...
4c + 4t + 3s =
4(3) + 4(2) + 3(4) =
12 + 8 + 12 = 32 legs...then u would have 32 legs
3 0
3 years ago
Suppose the ages of multiple birth mothers (4 or more births) are normally distributed with a mean age of 35.5 years and a stand
Ann [662]

Answer:

40.65% of these mothers are between the ages of 32 to 40

23.27% of these mothers are less than 30 years old

37.07% of these mothers are more than 38 years old

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 35.5, \sigma = 7.5

What percent of these mothers are between the ages of 32 to 40?

This is the pvalue of Z when X = 40 subtracted by the pvalue of Z when X = 32.

X = 40

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 35.5}{7.5}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 32

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 35.5}{7.5}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192

0.7257 - 0.3192 = 0.4065

40.65% of these mothers are between the ages of 32 to 40

What percent of these mothers are less than 30 years old?

This is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 35.5}{7.5}

Z = -0.73

Z = -0.73 has a pvalue of 0.2327

23.27% of these mothers are less than 30 years old

What percent of these mothers are more than 38 years old?

This is 1 subtracted by the pvalue of Z when X = 38.

Z = \frac{X - \mu}{\sigma}

Z = \frac{38 - 35.5}{7.5}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293

1 - 0.6293 = 0.3707

37.07% of these mothers are more than 38 years old

5 0
3 years ago
15 - 1.5(y - 5) - 7.5 simplified
antoniya [11.8K]

Answer:

I hope that is useful for you :)

Step-by-step explanation:

15 - 1.5y + 7.5 - 7.5 \\ 15 - 1.5y \\ 1.5(10 - y)

7 0
3 years ago
A group of ten students were given a statistics quiz. their scores were: 20, 19, 22, 20, 15, 18, 15, 21, 19, 20. the variance of
svet-max [94.6K]
<h3>Answer: Approximately 2.33</h3>

The variance is given to be 5.43

Apply the square root to the variance to get the standard deviation

s = standard deviation

v = variance

s = sqrt(v)

s = sqrt(5.43)

s = 2.330326 which is approximate

s = 2.33

I rounded to 2 decimal places as this is the number of decimal places used for the variance.

5 0
3 years ago
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