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ikadub [295]
3 years ago
8

Calculate the difference between the 1990-1997 average blue crab population and the 1998-2009 average blue crab population predi

ct the average blue crab population for 2010-2020 and explain
Mathematics
1 answer:
Karolina [17]3 years ago
5 0
The difference of the blue crab population From 1990-1997, the average was (800+750)/2 = 775; and from 1989-2009: (350+350)/2 = 350. I predict that from 2010 to 2020 the population will increase to about 500 because it seems to go on trends of increasing and decreasing.
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3 years ago
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At a shelter,15% of the dogs are puppies. There ate 60 dogs at the shelter. How many are puppies?
Anna71 [15]
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5 0
2 years ago
I NEED HELP QUICK
MAVERICK [17]

Answer:

m∠2= 180-30=150

m∠3= 30

m∠4=30

m∠5=150

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Step-by-step explanation:

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4 0
3 years ago
5 (2x + 10) = 50<br> What is the answer
KATRIN_1 [288]

9514 1404 393

Answer:

  x = 0

Step-by-step explanation:

You can eliminate parentheses and subtract 50.

  5(2x +10) = 50

  10x +50 = 50 . . . . use the distributive property

  10x = 0 . . . . . . . . . subtract 50 from both sides

  x = 0 . . . . . . . . . . . divide by 10

__

<em>Check</em>

  5(2·0 +10) = 50

  5(10) = 50 . . . . true

5 0
2 years ago
Find the value of x that makes the equation true:
uranmaximum [27]

Answer:

13

Step-by-step explanation:

6 0
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