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3 years ago

Which style do you like best out of the two choices And yes that is not me obviously

Mathematics

2 answers:

oee [108]3 years ago

7 0

Answer:

neither tbh, but if i have to choose id say the blonde style but in brown.. i like the wavy hair just not in blonde.

Step-by-step explanation:

Oksi-84 [34.3K]3 years ago

4 0

Answer:

tbh i like the first one its so simple but like so nice at the same time

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You have a rack that can hold 30 CDs. You can fit 7 more CDs on the rack before the rack is full. How many CDs are in the rack?

uysha [10]

X = number of cds on the rack

x + 7 = 30
x = 30 - 7
x = 23 <== so there are currently 23 cds on the rack

5 0

2 years ago

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Midpoint of the x intercepts of f(x)=(x-4)(x+4)

lorasvet [3.4K]

The x-intercept is defined to be the value of x when y is zero. Based on the graph of the function: f(x) = (x-4)(x+4), the x-intercepts are located at (-4, 0) and (4,0). At these points the graph intersects the x-axis. The midpoint of the x-intercepts is located at the middle of the two points. In this case, the graph shows that it is at the origin or at (0,0).

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2 years ago

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HELP I NEED HELP ASAP

xenn [34]

I think is B

I added 12 on the ride

6 0

3 years ago

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We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago

The equation 50=36.50+0.10m represent the additional number of messages roboerto can send with a budget of $50 .solve the equati

charle [14.2K]

Answer :
M = 135

Step by Step Explanation :
See the photo attached :) it’s kinda hard to explain in words but you cancel out the 36.50 by subtracting it on both sides, and then the equation becomes 13.50 = 0.10m. Since we have to get the m by itself, you cancel out the 0.10 by subtracting on both sides, and it leaves you with 135 = m

(Ignore my messy handwriting on a post it :3)

I hope this helped! If u have any questions feel free to comment on this!

4 0

2 years ago